Question

我正在尝试编写一个查询来搜索不在其超类中的子类属性，并返回超类的所有对象。目前，当我尝试执行person.get（“specialAttribute”）时，我得到一个NullPointerException。

@Inheritance(strategy = InheritanceType.JOINED)
@Entity
public abstract class Person {
    public String searchableAttribute;
}

@Entity
@Table( name = "normal_person" )
public class NormalPerson extends Person {

}

@Entity
@Table( name = "special_person" )
public class SpecialPerson extends Person {
    @Column(nullable = false, unique = true)
    public String specialAttribute;
}

// Controller method

    Root<Person> person = query.from(Person.class);
    query.where(
            builder.or(
                    builder.like(person.<String>get("specialAttribute"), "foo"),
                    builder.like(person.<String>get("searchableAttribute"), "foo")
            )
    );

Answer 1

在提示here提示后解决了我自己的问题。

Root<Person> person = query.from(Person.class);

Subquery<SpecialPerson> subQuery = query.subquery(SpecialPerson.class);
Root<SpecialPerson> specialPersonRoot = subQuery.from(SpecialPerson.class);

subQuery.select(specialPersonRoot);
subQuery.where(builder.like(specialPersonRoot.<String>get("specialAttribute"), "foo"));

query.where(
        builder.or(
                builder.in(person).value(subQuery)
                builder.like(person.<String>get("searchableAttribute"), "foo")
        )
);

如何使用JPA CriteriaQuery搜索子类属性？

1 个答案: