JPA - CriteriaQuery生成错误的SQL

Question

表Municipio：

@Id
@Basic(optional = false)
@NotNull
@Column(name = "Chave")
private Integer chave;
@Basic(optional = false)
@NotNull
@Size(min = 1, max = 40)
@Column(name = "Nome")
private String nome;
@Basic(optional = false)
@NotNull
@Column(name = "Cep")
private int cep;
@JoinColumn(name = "Uf", referencedColumnName = "Chave")
@ManyToOne(optional = false)
private Uf uf;

表Uf：

@Id
@Basic(optional = false)
@NotNull
@Size(min = 1, max = 2)
@Column(name = "Chave")
private String chave;
@Basic(optional = false)
@NotNull
@Size(min = 1, max = 20)
@Column(name = "Nome")
private String nome;
@OneToMany(cascade = CascadeType.ALL, mappedBy = "uf")
private Collection<Municipio> municipioCollection;

懒豆：

private Query createQuery(Class type, boolean count, Map<String, Object> filters, List<SortMeta> multiSortMeta) {
    CriteriaBuilder criteria = em.getCriteriaBuilder();
    CriteriaQuery query = criteria.createQuery((count ? Long.class : type));
    Root from = query.from(type);

    query.select((count ? criteria.count(from) : from));

    List filter = new ArrayList();  
    for (String filterProperty : filters.keySet()) {
        String filterValue = (String) filters.get(filterProperty);
        Expression literal = criteria.literal((String) filterValue);
        filter.add(criteria.like(from.get(filterProperty), literal));
    }
    query.where((Predicate[]) filter.toArray(new Predicate[filter.size()]));  

    if (!count) {
        if (multiSortMeta != null) {
            List<Order> order = new ArrayList();
            for (SortMeta sm : multiSortMeta) {
                if (!sm.getSortOrder().equals(SortOrder.DESCENDING)) {
                    order.add(criteria.asc(from.get(sm.getSortField())));
                } else {
                    order.add(criteria.desc(from.get(sm.getSortField())));
                }
            }
            query.orderBy(order);
        }
    }

    return em.createQuery(query);
}

没有关系的过滤列（Nome）。那是对的！

SQL ：

SELECT COUNT(Chave) FROM Municipio WHERE Nome LIKE ?

使用关系（Uf）过滤列。那是错的！

字段名称未出现在 WHERE 子句中。

SQL ：

SELECT COUNT(t0.Chave) FROM Municipio t0, Uf t1 WHERE ( LIKE ? AND (t1.Chave = t0.Uf))

生成以下错误：

Internal Exception: java.sql.SQLException: Incorrect syntax near the keyword 'LIKE'.

我该怎么办？