Question

SQL server 2008

您好

这是我的查询，它返回结果

SELECT * FROM Rooms
WHERE RoomID in 
(SELECT t1.RoomId FROM 
(Rooms t1 INNER JOIN 
(SELECT RoomID, SUM(quantity) AS QTY FROM Room_Item GROUP BY RoomID
HAVING SUM(Quantity) = 0) t2 ON t1.RoomID = t2.RoomID))

以上书面查询将返回房间的房间，其中没有任何项目（数量= 0），但现在我想过滤掉建筑物的结果，

我得到了具体建筑的房间清单，如下所示

select roomid from rooms where buildingblockid in (select buidingblockid from buildingblock where buildigID = 1)

所以我的查询将是

从已分配项目为0的房间表返回房间，并按建筑物编号= 1

过滤房间

表结构如下 - 仅显示基本字段

rooms => roomid(PK), buildingblockID(FK), roomname
room_item => roomitemid(PK), roomid(FK), itemid(FK), quantity
item => itemid(PK), itemname
buildingblock => buildingblockid(PK), buildingID(FK)
building => buildingID(PK), buildingName

Answer 1

您可以创建派生表以查找没有项目的房间，并将其加入buildingWiseRoom以过滤建筑物。

select buildingWiseRoom.roomID
from buildingWiseRoom
inner join
(
   select RoomID
     from Room_Item 
    group by RoomID 
   having SUM(Quantity) = 0
) itemlessRooms
  on buildingWiseRoom.roomID = itemlessRooms.roomID
where buildingWiseRoom.buildingID = 1

更新表格结构更新：

select rooms.roomID
from rooms
inner join buildingblock 
   on rooms.buildingblockID = buildingblock.buildingblockID
inner join
(
   select RoomID
     from Room_Item 
    group by RoomID 
   having SUM(Quantity) = 0
) itemlessRooms
  on rooms.roomID = itemlessRooms.roomID
where buildingblock.buildingID = 1

SQL服务器[加入查询+多个条件]

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