Question

表结构：
的 tblCustomer

Customer_id  created                 field1            field2        cardno       field14
------------------------------------------------------------------------------------------------    
1014         2010-05-25 12:51:59.547 Cell Phone        abc@lmn.com   1234567890   Test Card
1015         2010-08-15 12:51:59.547 Email             abc@xyz.com   2345678891   NULL

tbl_TransactionDishout

Trnx_id   offerNo   TerminalID      Created                  VirtualCard
-------------------------------------------------------------------
1         1014      170924690436418 2010-05-25 12:51:59.547  1234567890

tbl_transaction和tblCustomer之间的关系具有相同的cardno 是否有可能将结果作为以下日期记录得出：

               Enrolled   Enrolled as Email  Enrolled as Text Deals Redeemed   
<First Date>   7          5                  2                6
<Next Date>    9          3                  6               14

日期应该来自两个表，即使它没有记录......

Enrolled          - Total No of records that is summation of Enrolled as Email and Enrolled as Text.      
Enrolled as Email - Where field1 = 'Email' from tblCustomer table
Enrolled as Text  - Where field1 = 'cell phone' from tblCustomer table
Deals Redeemed    - Where field14 <> 'Test Card' from tblCustomer table and    
                    where DishoutResponsecode = '0000' from tbl_Transaction table

我现有的查询：

SELECT
convert(varchar, CAST(ISNULL(t1.created,t2.created) AS DATETIME), 111) created,
COUNT(CASE WHEN (t1.field1 = 'E-mail' or t1.field1 = 'Cell Phone')  and (t1.field14 <>  'Test Card'  or t1.field14 is null) THEN 1 END) Enrolled,
COUNT(CASE WHEN t1.field1 = 'E-mail'            and (t1.field14 <> 'Test Card'   and t1.field14 is null) THEN 1 END) Enrolled_as_Email,
COUNT(CASE WHEN t1.field1 = 'Cell Phone'        and (t1.field14 <> 'Test Card'   and t1.field14 is null) THEN 1 END) Enrolled_as_Cell,
COUNT(CASE WHEN t2.DishoutResponseCode = '0000' and (IsNull(t1.field14, '') <> 'Test Card') THEN 1 END) Deals_Redeemed  
FROM  tblCustomer AS t1
FULL OUTER JOIN
      tbl_TransactionDishout t2
ON  t1.cardno = t2.VirtualCard and t1.created = t2.created
GROUP BY
      convert(varchar, CAST(ISNULL(t1.created,t2.created) AS DATETIME),      111)
ORDER BY
      convert(varchar, CAST(ISNULL(t1.created,t2.created) AS DATETIME), 111) DESC

tblCustomer表格中的最后4-5条记录

created                 cardno               field14
----------------------------------------------------------
2012-03-07 10:03:00.034 1234007600101240    
2012-03-05 04:02:00.040 1234007600602122    
2012-03-01 06:25:50.400 1234010400972168     Test Card
2012-03-01 30:05:30.022 555566669999         Test Card
2012-03-01 50:50:20.450 666677778888         Test Card

tbl_TransactionDisout表格中的最后4-5条记录

created                 VirtualCard         DishoutResponseCode
-----------------------------------------------------------------------
2012-03-09 13:18:02.703 1234010400972168    0010
2012-03-09 13:17:35.307 1234010400972168    0002
2012-03-09 13:17:14.237 1234010400972168    0007
2012-03-09 13:16:57.650 1234010400972168    0002
2012-03-08 21:13:57.137 1234010400475686    0000
2012-03-08 16:50:38.273 1234010400972168    0002
2012-03-08 16:50:26.070 1234010400972168    0007
2012-03-08 16:49:49.793 1234010400972168    0002

因此，只有一张卡片有响应代码'0000'而且也不是'测试卡'..但是我得到的所有卡的代码='0000'并且还有'测试卡'以便表示field14无法比较，因为它来自不同的表和不同的日期..

Answer 1

当我使用您在主要问题中指定的数据时，这是我使用此查询返回的结果：

SELECT  
  convert(varchar, CAST(ISNULL(t1.created,t2.created) AS DATETIME), 111) created,  
  COUNT(CASE WHEN (t1.field1 = 'Email' or t1.field1 = 'Cell Phone')  and (t1.field14 <> 'Test Card'  or t1.field14 is null) THEN 1 END) Enrolled,
  COUNT(CASE WHEN t1.field1 = 'Email'            and (IsNull(t1.field14, '') <> 'Test Card') THEN 1 END) Enrolled_as_Email,  
  COUNT(CASE WHEN t1.field1 = 'Cell Phone'        and (IsNull(t1.field14, '') <> 'Test Card') THEN 1 END) Enrolled_as_Cell,  
  COUNT(CASE WHEN t2.DishoutResponseCode = '0000' and (IsNull(t1.field14, '') <> 'Test Card') THEN 1 END) Deals_Redeemed  
FROM  
  tblCustomer AS t1  
FULL OUTER JOIN  
  tbl_TransactionDishout t2  
    ON  t1.cardno = t2.VirtualCard  
    AND t1.created = t2.created  
GROUP BY  
  convert(varchar, CAST(ISNULL(t1.created,t2.created) AS DATETIME), 111)  
ORDER BY  
  convert(varchar, CAST(ISNULL(t1.created,t2.created) AS DATETIME), 111) DESC

结果：

created                        Enrolled    Enrolled_as_Email Enrolled_as_Cell Deals_Redeemed
------------------------------ ----------- ----------------- ---------------- --------------
2012/03/09                     0           0                 0                0
2012/03/08                     0           0                 0                1
2012/03/07                     1           0                 1                0
2012/03/05                     1           0                 1                0
2012/03/01                     0           0                 0                0

多个连接查询和子查询

1 个答案: