Question

我有两张桌子，一张用于开放，另一张用于预订。预订表中的条目总是指开口，每个开口可能有多个预订。我想提取所有预订与bookingType 'C'不同的空缺。

E.g。



如果开口有3个A，B和C类预订，则不应该出现   在结果



如果一个开口只有A和B类型的预订，它应该显示在   结果

以下是我尝试的但是它不正确，因为示例1失败了：

select op.id, bo.id 
  from opening op
  left join booking bo on bo.openingId = op.id
  where bo.bookingType != 'C';

以下是涉及时间间隔的完整查询：

select op.id, bo.id 
  from opening op
  left join booking bo on bo.openingId = op.id
  where ((bo.arrivalDate < '2009/06/20' AND bo.departureDate <= '2009/06/20') OR 
         (bo.arrivalDate >= '2009/06/27' AND bo.departureDate > '2009/06/27'))

我以前称之为bookingType的实际上是通过两列arrivalDate和departureDate定义的时间间隔：在上面的示例中，我需要所有未预订的空缺在20th June 2009和27th June 2009。

之间

Answer 1

SELECT op.id 
FROM opening op 
WHERE op.id NOT IN 
     (SELECT b.openingid 
      FROM booking b 
      WHERE b.bookingtype='C')

日期更改：

SELECT op.id 
FROM opening op 
WHERE op.id NOT IN 
     (SELECT b.openingid 
      FROM booking b 
      WHERE (b.arrivalDate BETWEEN '2009/06/20' AND '2009/06/27') 
             OR 
            (b.departureDate BETWEEN  '2009/06/20' and '2009/06/27')
     )

Answer 2

这是一个没有连接的简单版本，你甚至不需要开口表：

select openingId, id
from booking
where openingId not in (
    select openingId
    from booking
    where bookingType = 'C'
)

Answer 3

@Frankie - 不需要NOT IN子句。您也可以使用Left-Anti-Semi Join - 就像这样：

SELECT op.id 
FROM opening op 
LEFT OUTER JOIN booking b ON op.id = b.openingid AND b.bookingtype = 'C'
WHERE b.OpeningID IS NULL

和此：

SELECT op.id 
FROM opening op 
LEFT OUTER JOIN booking b ON op.id = b.OpeningID
 AND b.ArrivalDate BETWEEN '2009/06/20' AND '2009/06/27'  
 AND b.DepartureDate BETWEEN '2009/06/20' AND '2009/06/27'
WHERE b.OpeningID IS NULL

Answer 4

select opid, boid from 
   (select op.id opid, bo.id boid, bo.bookingType bookingType 
       from 
       openings op left outer join bookings bo on op.id = bo.id
   )
where bookingType <> 'C'

SQL查询 - 我哪里错了？

4 个答案: