$foot = mysql_query("SELECT count(*)
FROM tblQA
WHERE intResponseID = ''
AND cCategory = 'Football' as qcount,
(SELECT max(dPostDateTime)
FROM tblQA
WHERE intResponseID = ''
AND cCategory = 'Football') as lastq");
$football = mysql_fetch_array($foot);
echo "<td class='forum'>" . $footbll['qcount'] . "</td>";
echo "<td class='forum'>" . $footbll['lastq'] . "</td>";
这不会在我的表格中显示任何内容。我没有发布整个HTML代码,我的表结构很好。
答案 0 :(得分:3)
使用:
$foot = mysql_query("SELECT COUNT(*) AS qcount,
MAX(dPostDateTime) AS lastq
FROM tblQA
WHERE intResponseID = ''
AND cCategory = 'Football' ");
$football = mysql_fetch_array($foot);
echo "<td class='forum'>" . $football['qcount'] . "</td>";
echo "<td class='forum'>" . $football['lastq'] . "</td>";
我重写了你的查询,它可以在一个语句中完成。
答案 1 :(得分:1)
如果这是您的文字代码,则$footbll
中会出现拼写错误。
答案 2 :(得分:0)
你应该有类似的东西:
while ($football = mysql_fetch_array($foot)) {
echo "<td class='forum'>" . $football['qcount'] . "</td>";
/* yadda yadda yadda */
}
您的代码中也有一些拼写错误。
答案 3 :(得分:0)
我认为你错过了,
所在的组合器:...qcount, (SELECT...
答案 4 :(得分:0)
查询没有任何意义,我非常惊讶它会在您的数据库GUI中返回一些内容。
如果您不想更改语法,则必须执行以下操作:
SELECT (SELECT COUNT(*) FROM tblQA) AS qcount, (SELECT MAX(dPOstDateTime) FROM tblQA) AS lastq -- i didn't add the conditions
但是,通过执行此查询可以轻松完成:
SELECT COUNT(*) AS qcount,
MAX(dPostDateTime) AS lastq
FROM tblQA
WHERE intResponseID = ''
AND cCategory = 'Football'
请注意intResponseID听起来像是一个整数,你把它与空字符串比较似乎很奇怪......
答案 5 :(得分:0)
好的,这是我的解决方案。我弄清楚了:
$foot = mysql_query("SELECT count(*), max(dPostDateTime) FROM tblQA WHERE intResponseID = '' AND cCategory = 'Football'");
$football = mysql_fetch_assoc($foot);
echo "<td class='forum'><center>" . $football['count(*)'] . "</center></td>";
echo "<td class='forum'><center>" . $football['max(dPostDateTime)'] . "</center></td>";