Question

我需要帮助将2个变量连接成1个var，或者任何其他方法将这些变量连接在一起...

我的目的是制作一个艺术ascii发生器，它需要显示一个特定的单词来生成它...在这个例子中我只会显示单词“a”，但我不能，打印功能打印var“（[0,4]）”的内容，我需要连接变量并像处理命令一样处理它，而不是像字符串......：

# encoding:utf-8

threexfive = '
    #         #      ##     
 ## ### ### ### ###  #  ### 
# # # # #   # # ##  ### # # 
### ### ### ### ###  #   ## 
                    ##  ### 
'

# The long of the letters a to f
threexfive_longs = '
a=[0,4]
b=[4,4]
c=[8,4]
d=[12,4]
e=[16,4]
f=[20,4]
'
string = ''
word = 'a'

word.each_char do |char|
  $long = threexfive_longs.split(char).last.split(']').first.split('=').last + "]"

 threexfive.each_line do |type|

   # This don't works:
   string = type + $long
   print string


   # But this works  :(
   # print type[20,4], type[0,4], type[8,4], type[16,4], "\n"

 end 
end

区别在于：

   # This doesn't work:
   string = type + $long
   print string

输出：

Output

   # But this works  :(
   print type[0,4], "\n"

输出：

Output

Answer 1

您可以尝试单独编写所有行，然后将其与join("\n")连接，如下例所示。我强烈建议为char位置使用适当的数据结构（或称为“longs”）。在这个例子中，我使用了哈希。

# encoding:utf-8

threexfive = ' 
    #         #      ##     
 ## ### ### ### ###  #  ### 
# # # # #   # # ##  ### # # 
### ### ### ### ###  #   ## 
                    ##  ### 
'

char_pos = { 
  :a => 0..3,
  :b => 4..7,
  :c => 8..11,
  :d => 12..15,
  :e => 16..19,
  :f => 20..23
}

word = 'cafe'

result = Array.new(threexfive.lines.count){''}     # array with n empty lines
word.each_char do |char|
  pos = char_pos[char.to_sym]                      # get position of char
  threexfive.lines.each_with_index do |line,index|
    next if index == 0                             # first line of threexfive is empty -> skip
    result[index] << line[pos]                     # compose individual lines
  end 
end
result = result.join("\n")                         # join the lines with \n (newline)

puts result                                        # print result

该程序的输出是：

         ##     
###  ##  #  ### 
#   # # ### ##  
### ###  #  ### 
        ##

如何在Ruby中连接它

1 个答案: