Question

我有一个xts序列的股票交易事件，我想处理它以生成1分钟的OHLC时间序列。例如这组交易：

Timestamp   Price  Size
9:30:00.123 12.32  200
9:30.00.532 12.21  100
9:30.32.352 12.22  500
9:30.45.342 12.35  200

应该导致9:30:00记录：

Timestamp Open  High  Low   Close
9:30:00   12.32 12.35 12.21 12.35

我接近这个的方法是按分钟分割原始交易系列：

myminseries = do.call(rbind, lapply(split(mytrades, "minutes"), myminprocessing))

这产生了我想要的记录，但是有一个问题：如果股票在给定的一分钟内没有任何交易，我将完全错过那一分钟记录。我想要的是为缺少的交易分钟提供全0记录。例如，如果在9:31:00没有任何交易我应该：

Timestamp  Open  High  Low   Close
9:30:00    12.32 12.35 12.21 12.35
9:31:00    0     0     0     0
9:32:00    12.40 12.42 12.38 12.42

如何回填1分钟系列？或者我应该使用与split（）完全不同的方法？

Answer 1

如果在给定的分钟内没有交易，to.minutes“将完全错过该分钟记录”。你可以通过合并零宽度，严格规则的xts系列来解决这个问题。

## Make sample data
> x <- xts(cumsum(rnorm(600, 0, 0.2)), Sys.time() - 600:1) # 10 minutes of secondly data
> # remove all data from a couple different minutes
> x['2012-03-19 17:33'] <- NA
> x['2012-03-19 17:35'] <- NA
> x <- na.omit(x)
> 
> ## Convert to minutes
> xm <- to.minutes(x)
> head(xm)
                      x.Open   x.High       x.Low    x.Close
2012-03-19 17:31:59 0.1945049 1.661000 -0.35943057  1.6610000
2012-03-19 17:32:59 1.7283877 1.728388 -0.69288918  1.1398868
2012-03-19 17:34:59 2.0529582 2.603881 -0.80532315 -0.8053232
2012-03-19 17:36:59 0.5314270 1.189609 -0.94996548  0.5807342
2012-03-19 17:37:59 0.3761700 1.943363  0.04046976  0.9101720
2012-03-19 17:38:59 1.0614807 1.722110 -0.22147145  1.4075637
> axm <- align.time(xm) #align times to begining of next period
> 
> # to make strictly regular, create an xts object that has values for each minute
> tmp <- xts(, seq.POSIXt(start(axm), end(axm), by='min'))
> out <- cbind(tmp, axm)
> out
                       x.Open      x.High       x.Low     x.Close
2012-03-19 17:32:00  0.19450494  1.66100005 -0.35943057  1.66100005
2012-03-19 17:33:00  1.72838773  1.72838773 -0.69288918  1.13988679
2012-03-19 17:34:00          NA          NA          NA          NA
2012-03-19 17:35:00  2.05295818  2.60388093 -0.80532315 -0.80532315
2012-03-19 17:36:00          NA          NA          NA          NA
2012-03-19 17:37:00  0.53142696  1.18960858 -0.94996548  0.58073422
2012-03-19 17:38:00  0.37616997  1.94336348  0.04046976  0.91017202
2012-03-19 17:39:00  1.06148070  1.72211018 -0.22147145  1.40756366
2012-03-19 17:40:00  1.28437005  1.28437005 -0.62691689 -0.62691689
2012-03-19 17:41:00 -0.56820166  0.90339983 -0.77554869  0.26101945
2012-03-19 17:42:00 -0.07443971 -0.07443971 -0.07443971 -0.07443971
> na.locf(out)
                       x.Open      x.High       x.Low     x.Close
2012-03-19 17:32:00  0.19450494  1.66100005 -0.35943057  1.66100005
2012-03-19 17:33:00  1.72838773  1.72838773 -0.69288918  1.13988679
2012-03-19 17:34:00  1.72838773  1.72838773 -0.69288918  1.13988679
2012-03-19 17:35:00  2.05295818  2.60388093 -0.80532315 -0.80532315
2012-03-19 17:36:00  2.05295818  2.60388093 -0.80532315 -0.80532315
2012-03-19 17:37:00  0.53142696  1.18960858 -0.94996548  0.58073422
2012-03-19 17:38:00  0.37616997  1.94336348  0.04046976  0.91017202
2012-03-19 17:39:00  1.06148070  1.72211018 -0.22147145  1.40756366
2012-03-19 17:40:00  1.28437005  1.28437005 -0.62691689 -0.62691689
2012-03-19 17:41:00 -0.56820166  0.90339983 -0.77554869  0.26101945
2012-03-19 17:42:00 -0.07443971 -0.07443971 -0.07443971 -0.07443971

或者，如果在没有值时你真的想要零，你可以做out[is.na(out)] <- 0

Answer 2

有to.period()个函数，例如xts中的to.minute()可以执行此操作。

德克

R xts：从第二个事件生成1分钟的时间序列

2 个答案: