Question

我通过以下代码发送Post请求：

try
            {
                string responseContent;
                request = (HttpWebRequest)WebRequest.Create(url);
                request.CookieContainer = cookieContainer;
                // Set Method to "POST"
                request.Method = "POST";
                // Set the content type of the WebRequest
                request.ContentType = "application/x-www-form-urlencoded";
                request.Proxy = GlobalProxySelection.GetEmptyWebProxy();
                request.UserAgent = "Mozilla/5.0 (Windows; U; Windows NT 6.1; de; rv:1.9.2.3) Gecko/20100401 Firefox/3.6.3";
                // Set the content length
                ASCIIEncoding encoding = new ASCIIEncoding();
                byte[] byteArray = encoding.GetBytes(requestCommand);
                request.ContentLength = byteArray.Length;
                // Get the request stream
                using (Stream requestStream = request.GetRequestStream())
                {
                    // Write the "POST" data to the stream
                    requestStream.Write(byteArray, 0, byteArray.Length);
                }
                using (HttpWebResponse response = (HttpWebResponse)request.GetResponse())
                {
                    using (Stream responseStream = response.GetResponseStream())
                    {
                        using (BufferedStream buffer = new BufferedStream(responseStream))
                        {
                            using (StreamReader reader = new StreamReader(buffer))
                            {
                                responseContent = reader.ReadToEnd();
                            }
                        }
                    }
                }
                return responseContent;
            }
            catch (Exception ex)
            {
                return ex.Message;
            }
}

它运作正常。但下面的代码行很慢。

using (StreamReader reader = new StreamReader(buffer))
{
   responseContent = reader.ReadToEnd();
}

我不知道为什么！我花了更多时间找出解决方案，例如set proxy = null，...但没有结果。有没有办法忽略这一行。我不需要接收响应数据。我试过通过以下方式替换这些行：

using (Stream responseStream = response.GetResponseStream())
{
   responseStream.Flush();
   responseStream.Close();
}

但我无法正确发送邮件请求。请帮我。非常感谢！

Answer 1

如果你根本不关心响应或它是否失败，你可以在新线程上排队响应并忽略它。

using (Stream requestStream = request.GetRequestStream())
{
    // Write the "POST" data to the stream
    requestStream.Write(byteArray, 0, byteArray.Length);
}

// now put the get response code in a new thread and immediately return
ThreadPool.QueueUserWorkItem((x) =>
{
    using (var objResponse = (HttpWebResponse) request.GetResponse())
    {
        responseStream = new MemoryStream();
        objResponse.GetResponseStream().CopyTo(responseStream);
        responseStream.Seek(0, SeekOrigin.Begin);
     }
});

如何忽略发送Post请求时的响应数据？

1 个答案: