Question

我在Android上使用了一个Web服务“http://www.w3schools.com/webservices/tempconvert.asmx”并尝试访问其方法“CelsiusToFahrenheit”并在清单文件中添加了Internet权限但是当我运行时模拟器显示错误结果的项目，而不是将摄氏温度转换为华氏温度。任何帮助将不胜感激。这是我的代码：

public class FinalKsoap extends Activity {
/** Called when the activity is first created. */

public static final String NAMESPACE = "http://tempuri.org/";
public static final String SOAP_ACTION = "http://tempuri.org/CelsiusToFahrenheit";
public static final String URL =  
          "http://www.w3schools.com/webservices/tempconvert.asmx";
public static final String METHOD_NAME = "CelsiusToFahrenheit";
TextView tv,tv1;
    @Override
    public void onCreate(Bundle savedInstanceState) {
       super.onCreate(savedInstanceState);
       setContentView(R.layout.main);
       tv = (TextView)findViewById(R.id.text01); 
       tv1 = (TextView)findViewById(R.id.text02);
       SoapObject Request = new SoapObject(NAMESPACE, METHOD_NAME);
       Request.addProperty("Celsius", "32");
       SoapSerializationEnvelope soapEnvelope = new
            SoapSerializationEnvelope(SoapEnvelope.VER11);
       soapEnvelope.dotNet = true;
       soapEnvelope.setOutputSoapObject(Request);

       AndroidHttpTransport aht = new AndroidHttpTransport(URL); 
       try
    {

            aht.call(SOAP_ACTION, soapEnvelope);
            SoapPrimitive result = (SoapPrimitive)soapEnvelope.getResponse();
            tv.setText("Status : " + result);
    }
   catch(Exception e)
    {
        e.printStackTrace();
    }

    tv1.setText("Hellooooooo"); 

}

}

Answer 1

这是一个常见的错误。据我所知，getResponse（）方法总是只返回true（命令成功）或false（命令失败）。

如果您想要Web服务返回的数据，则必须使用以下代码：

public static void test() throws IOException, XmlPullParserException {
    SoapObject Request = new SoapObject(NAMESPACE, METHOD_NAME);
    Request.addProperty("Celsius", "32");
    SoapSerializationEnvelope soapEnvelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
    soapEnvelope.dotNet = true;
    soapEnvelope.setOutputSoapObject(Request);

    HttpTransportSE androidHttpTransport = new HttpTransportSE(URL);
    androidHttpTransport.call(SOAP_ACTION, soapEnvelope);
    SoapPrimitive result = (SoapPrimitive) soapEnvelope.getResponse();
    SoapObject resultsRequestSOAP = (SoapObject) soapEnvelope.bodyIn;
    System.out.println(result); // prints "89.6"
    if (resultsRequestSOAP != null) {
        System.out.println(resultsRequestSOAP);
      Object o = resultsRequestSOAP.getProperty("CelsiusToFahrenheitResult");
      System.out.println(o); // prints "89.6"
    }
}

Android Emulator不显示Web服务的结果并将结果“false”而不是添加

1 个答案: