Question

我有以下问题的示例代码。运行这个，我希望（如果你在lineedit中键入内容），将会调用A.updateValue插槽两次，从而显示'a.updatevalue called'和'a2.updatevalue called' 但是，它只调用一次，即self.a2对象而不是self.a对象，后者从工作线程发送到GUI线程。我该如何解决这个问题，以便这段代码也能触发self.a对象的插槽？

谢谢你，大卫

import os, sys
from PyQt4.QtCore import * 
from PyQt4.QtGui import * 

class A(QObject): 
    def __init__(self, name): 
        QObject.__init__(self) 
        self.name = name
    def updateValue(self, value): 
        print(self.name + ".updatevalue called")

class workerthread(QThread):
    def __init__(self, parent=None):
        QThread.__init__(self, parent)
    def run(self):
        a = A('a')
        QObject.emit(self, SIGNAL("mySignal"), a)

class Main(QMainWindow):
    def __init__(self):
        QMainWindow.__init__(self)
        self.centralwidget = QWidget(self)
        self.hbox = QHBoxLayout()
        self.centralwidget.setLayout(self.hbox)

    def update(self, a):
        self.a = a
        edit = QLineEdit("", self)
        self.hbox.addWidget(edit)
        edit.textChanged.connect(self.a.updateValue)
        self.a2 = A('a2')
        edit.textChanged.connect(self.a2.updateValue)

if __name__ == "__main__":
    app = QApplication(sys.argv)
    gui = Main()
    worker = workerthread()
    worker.connect(worker, SIGNAL('mySignal'), gui.update)
    worker.start()
    gui.show()
    sys.exit(app.exec_())

Answer 1

初始化a

时定义workerThread

class workerthread(QThread):
    def __init__(self, parent=None):
        QThread.__init__(self, parent)
        self.a = A('a') 
    def run(self):
        QObject.emit(self, SIGNAL("mySignal"), self.a)

如何调试pyqt信号/插槽连接，可能是线程问题

1 个答案: