此处我的联系人姓名显示在列表视图中。点击列表,我会获得ContactName
和Contact Id
。我想通过使用Phone number
或Contact ID
来抓取Contact name
,请帮助我。
这是我的代码
void ReadContacts(String sort) {
final Uri uri = ContactsContract.Contacts.CONTENT_URI;
final String[] projection = new String[] {
ContactsContract.Contacts._ID,
ContactsContract.Contacts.DISPLAY_NAME
};
//boolean mShowInvisible = false;
String selection = ContactsContract.Contacts.IN_VISIBLE_GROUP + " = '1'";
String[] selectionArgs = null;
final String sortOrder = ContactsContract.Contacts.DISPLAY_NAME + " COLLATE LOCALIZED ASC";
m_curContacts = managedQuery(uri, projection, selection, selectionArgs, sortOrder);
String[] fields = new String[] {ContactsContract.Data.DISPLAY_NAME};
m_slvAdapter = new SimpleCursorAdapter(this,
android.R.layout.simple_list_item_1,
m_curContacts,
fields,
new int[] {android.R.id.text1});
m_slvAdapter.setFilterQueryProvider(new FilterQueryProvider() {
public Cursor runQuery(CharSequence constraint) {
Log.d(LOG_TAG, "runQuery constraint:"+constraint);
String selection = ContactsContract.Contacts.IN_VISIBLE_GROUP + " = '1'" +
" AND "+ ContactsContract.Contacts.DISPLAY_NAME + " LIKE '%"+constraint+"%'";
String[] selectionArgs = null;//new String[]{"'1'"};//, };
Cursor cur = managedQuery(uri, projection, selection, selectionArgs, sortOrder);
return cur;
}
});
m_lvContacts.setAdapter(m_slvAdapter);
// cur.close();
}
public void onItemClick(AdapterView<?> arg0, View v, int position, long id) {
ContentResolver cr;
Cursor cursor = (Cursor) m_lvContacts.getItemAtPosition(position);
String szDisplayName = cursor.getString(cursor.getColumnIndexOrThrow( ContactsContract.Contacts.DISPLAY_NAME));
String szId = cursor.getString(cursor.getColumnIndexOrThrow( ContactsContract.Contacts._ID));
int nId = cursor.getInt(cursor.getColumnIndexOrThrow( ContactsContract.Contacts._ID));
Log.d(LOG_TAG, "Item click:"+position+" szId:"+szId+" nId:"+nId+" Data:"+szDisplayName);
Toast.makeText(getBaseContext(), "Item click:"+phoneNumber+" szId:"+szId+" nId:"+nId+" Data:"+szDisplayName, Toast.LENGTH_SHORT).show();
}
答案 0 :(得分:20)
试试这个
ArrayList<String> phones = new ArrayList<String>();
Cursor cursor = mContentResolver.query(
CommonDataKinds.Phone.CONTENT_URI,
null,
CommonDataKinds.Phone.CONTACT_ID +" = ?",
new String[]{id}, null);
while (cursor.moveToNext())
{
phones.add(cursor.getString(cursor.getColumnIndex(CommonDataKinds.Phone.NUMBER)));
}
cursor.close();
return(phones);
答案 1 :(得分:2)
试试这个
public void getNameUsingContactId(String contactId){
String cContactIdString = ContactsContract.Contacts._ID;
Uri cCONTACT_CONTENT_URI = ContactsContract.Contacts.CONTENT_URI;
String cDisplayNameColumn = ContactsContract.Contacts.DISPLAY_NAME;
String selection = cContactIdString + " = ? ";
String[] selectionArgs = new String[]{String.valueOf(contactId)};
Cursor cursor = mContext.getContentResolver().query(cCONTACT_CONTENT_URI, null, selection, selectionArgs, null);
if ((cursor != null) && (cursor.getCount() > 0)) {
cursor.moveToFirst();
while ((cursor != null) && (cursor.isAfterLast() == false)) {
if (cursor.getColumnIndex(cContactIdString) >= 0) {
if (contactId.equals(cursor.getString(cursor.getColumnIndex(cContactIdString)))) {
String name = cursor.getString(cursor.getColumnIndex(cDisplayNameColumn));
break;
}
}
cursor.moveToNext();
}
}
if (cursor != null)
cursor.close();
}
答案 2 :(得分:0)
您可以在数据表中找到phonenumbers。在rawcontacts表中找到相应的原始联系人ID(使用联系人ID作为条件),使用这些原始联系人ID查询数据表。 phonenumber将具有某种mime类型(现在远离文档),因此您可以识别它们。 希望这有帮助!
提示:从您的模拟器/设备复制contacts2.db数据库,并使用Squirrel(SQLite jdbc驱动程序)在联系人数据库中查找。数据库位于/ data / data /下查找列表中的联系人。)
答案 3 :(得分:0)
伙计们我得到了答案:
如果您需要,请使用此代码:
Cursor cursor = (Cursor) m_lvContacts.getItemAtPosition(position);
String szDisplayName = cursor.getString(cursor.getColumnIndexOrThrow( ContactsContract.Contacts.DISPLAY_NAME));
String szId = cursor.getString(cursor.getColumnIndexOrThrow( ContactsContract.Contacts._ID));
int nId = cursor.getInt(cursor.getColumnIndexOrThrow( ContactsContract.Contacts._ID));
long l = Long.parseLong(szId);
int type=ContactsContract.CommonDataKinds.Phone.TYPE_MOBILE;
cursor = getContentResolver().query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI,
null,
ContactsContract.CommonDataKinds.Phone.CONTACT_ID+"='"+szId+"'",
null, null);
int phoneNumberIndex = cursor
.getColumnIndexOrThrow(ContactsContract.CommonDataKinds.Phone.NUMBER);
Log.d(TAG, String.valueOf(cursor.getCount()));
if (cursor != null) {
Log.v(TAG, "Cursor Not null");
try {
if (cursor.moveToNext()) {
Log.v(TAG, "Moved to first");
Log.v(TAG, "Cursor Moved to first and checking");
phoneNumber = cursor.getString(phoneNumberIndex);
System.out.println("HAGSd"+phoneNumber);
}
} finally {
Log.v(TAG, "In finally");
cursor.close();
}
答案 4 :(得分:0)
public static final String contactIdByPhoneNumber(Context ctx, String phoneNumber) {
String contactId = null;
if (phoneNumber != null && phoneNumber.length() > 0) {
ContentResolver contentResolver = ctx.getContentResolver();
Uri uri = Uri.withAppendedPath(ContactsContract.PhoneLookup.CONTENT_FILTER_URI, Uri.encode(phoneNumber));
String[] projection = new String[] { PhoneLookup._ID };
Cursor cursor = contentResolver.query(uri, projection, null, null, null);
if (cursor != null) {
while (cursor.moveToNext()) {
contactId = cursor.getString(cursor.getColumnIndexOrThrow(PhoneLookup._ID));
}
cursor.close();
}
}
return contactId;
}