我正在尝试通过他们的contactId查找联系人的电话号码,bll结果将返回 - 电话号码:1
我尝试过围绕SO使用其他示例,但我一直在光标上获得0计数
Uri uri = ContentUris.withAppendedId(Data.CONTENT_URI, contactId);
Log.i(TAG, "Locate Contact by Id: " + contactId + " at Uri: " + uri.toString());
Cursor cursor = this.getContentResolver().query(uri, null, null, null, null);
try {
if (cursor.moveToFirst()) {
Log.i(TAG, "Phone Number: " + cursor.getString(cursor.getColumnIndex(Phone.NUMBER)));
}
} finally {
cursor.close();
}
答案 0 :(得分:6)
试试这个:
private ArrayList<String> getPhoneNumbers(String id)
{
ArrayList<String> phones = new ArrayList<String>();
Cursor cursor = mContentResolver.query(
CommonDataKinds.Phone.CONTENT_URI,
null,
CommonDataKinds.Phone.CONTACT_ID +" = ?",
new String[]{id}, null);
while (cursor.moveToNext())
{
phones.add(cursor.getString(cursor.getColumnIndex(CommonDataKinds.Phone.NUMBER)));
}
cursor.close();
return(phones);
}
答案 1 :(得分:2)
我最终是通过Phone.LOOKUP_KEY
而不是Phone.CONTACT_ID
;
private HashMap<String, CharSequence> lookupPhoneNumbers(String lookupKey)
{
HashMap<String, CharSequence> numbers = new HashMap<String, CharSequence>();
Cursor cursor = getContext().getContentResolver().query(Phone.CONTENT_URI, null, Phone.LOOKUP_KEY + " = ?", new String[] { lookupKey }, null);
try
{
while (cursor.moveToNext())
{
String phoneNumber = cursor.getString(cursor.getColumnIndex(Phone.NUMBER));
int type = cursor.getInt(cursor.getColumnIndex(Phone.TYPE));
CharSequence phoneLabel = Phone.getTypeLabel(getResources(), type, "Undefined");
// boolean isPrimary = (cursor.getInt(cursor.getColumnIndex(Phone.IS_PRIMARY)) == 1);
numbers.put(phoneNumber, phoneLabel);
}
} finally
{
cursor.close();
}
return numbers;
}