Question

在我的应用程序中我想获取并列出联系人姓名他们的号码和我尝试的电子邮件地址，但ContactsContract.CommonDataKinds.Email和ContactsContract.Contacts.DISPLAY_NAME冲突，所以如果可能的话，无法提供我尝试的一些代码以下代码

    ContentResolver cr = getContentResolver();
    Cursor cur = cr.query(ContactsContract.Contacts.CONTENT_URI,
            null, null, null, null);
    if (cur.getCount() > 0) {
        while (cur.moveToNext()) {
            String id = cur.getString(cur.getColumnIndex(ContactsContract.Contacts._ID));
            String name = cur.getString(cur.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME));
            if (Integer.parseInt(cur.getString(
                    cur.getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER))) > 0) {
                 Cursor pCur = cr.query(
                         ContactsContract.CommonDataKinds.Phone.CONTENT_URI, 
                         null, 
                         ContactsContract.CommonDataKinds.Phone.CONTACT_ID +" = ?", 
                         new String[]{id}, null);
                 while (pCur.moveToNext()) {
                     String phoneNo = pCur.getString(pCur.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
                     Toast.makeText(NativeContentProvider.this, "Name: " + name + ", Phone No: " + phoneNo, Toast.LENGTH_SHORT).show();
                 } 
            pCur.close();
        }
        }
    }
    String id = cur.getString(cur.getColumnIndex(ContactsContract.Contacts._ID));
    Cursor emailCur = cr.query(
            ContactsContract.CommonDataKinds.Email.CONTENT_URI,
            null,
            ContactsContract.CommonDataKinds.Email.CONTACT_ID + " = ?",
            new String[]{id}, null);
    while (emailCur.moveToNext()) {
        // This would allow you get several email addresses
            // if the email addresses were stored in an array
        String email = emailCur.getString(
                      emailCur.getColumnIndex(ContactsContract.CommonDataKinds.Email.DATA));
        String emailType = emailCur.getString(
                      emailCur.getColumnIndex(ContactsContract.CommonDataKinds.Email.TYPE));

      System.out.println("Email " + email + " Email Type : " + emailType);
    }
    emailCur.close();

Answer 1

看起来你的代码问题可能是你想要的应该在两个单独的查询中。

查询电子邮件帐户或电话号码列表使用常见问题，例如ContactsContract.CommonDataKinds，URI：ContactsContract.CommonDataKinds.Email.CONTENT_URI。

查询非名称列表的实际Contact属性将使用ContactsContract.Contacts中的常量，URI：基于从Contacts.CONTENT_URI返回的数据。

信息并非全部存储在同一个地方，这可能是可能存在冲突的原因。

Answer 2

 switch (reqCode) {
        case (REQUEST_CODE_email):
            if (resultCode == Activity.RESULT_OK) {
                Uri contactData = data.getData();
                Cursor c = getContentResolver().query(contactData, null, null, null, null);
                if (c.moveToFirst()) {
                    String contactId = c.getString(c.getColumnIndex(ContactsContract.Contacts._ID));
                    String hasNumber = c.getString(c.getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER));
                    String num = "";
                    if (Integer.valueOf(hasNumber) == 1) {
                        Cursor numbers = getContentResolver().query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI, null, ContactsContract.CommonDataKinds.Phone.CONTACT_ID + " = " + contactId, null, null);
                        while (numbers.moveToNext()) {
                            num = numbers.getString(numbers.getColumnIndex(ContactsContract.CommonDataKinds.Phone.CONTACT_ID));
                            //Toast.makeText(getApplicationContext(), "Number=" + num, Toast.LENGTH_LONG).show();

                            //asdasdasdsa
                            if(getEmail(num).isEmpty()){
                                Toast.makeText(this, "Email Not Found In That Contact Try Another", Toast.LENGTH_SHORT).show();
                            }
                            else {
                                edt_email_contact.setText("" + getEmail(num));
                            }                            }
                    }
                }
                break;
            }
         case (REQUEST_CODE_number):
            if (resultCode == Activity.RESULT_OK) {
                Uri contactData = data.getData();
                Cursor c = getContentResolver().query(contactData, null, null, null, null);
                if (c.moveToFirst()) {
                    String contactId = c.getString(c.getColumnIndex(ContactsContract.Contacts._ID));
                    String hasNumber = c.getString(c.getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER));
                    String num = "";
                    if (Integer.valueOf(hasNumber) == 1) {
                        Cursor numbers = getContentResolver().query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI, null, ContactsContract.CommonDataKinds.Phone.CONTACT_ID + " = " + contactId, null, null);
                        while (numbers.moveToNext()) {
                            num = numbers.getString(numbers.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
                            //Toast.makeText(getApplicationContext(), "Number=" + num, Toast.LENGTH_LONG).show();



                            edt_email_contact.setText("" + num);
                        }
                    }
                }
                break;
            }

    }

无法获取本地电话联系人姓名，手机号码和电子邮件地址

2 个答案: