Question

我是javascript的新手，请你帮我转换为JSON格式到普通数组

             {"data": [
             {"name": "Bhengu","surname":"Nathi"},
             {"name": "Tsunami","surname":"Msipha"},
             { "name": "Fish","surname":"Lee"}
             ]};


             data= [
             {name: Bhengu, surname: Nathi},
             {name: Tsunami, surname: Msipha},
             { name: Fish, surname: Lee}
              ];

Answer 1

你可以使用php的json_decode功能

$json = '{"data": [{ "name": "Bhengu","surname":"Nathi"}, { "name": "Tsunami","surname":"Msipha"}, { "name": "Fish","surname":"Lee"} ]}';
$data = json_decode($json);
var_dump($data);

输出将是：

object(stdClass)[1]
  public 'data' => 
    array
      0 => 
        object(stdClass)[2]
          public 'name' => string 'Bhengu' (length=6)
          public 'surname' => string 'Nathi' (length=5)
      1 => 
        object(stdClass)[3]
          public 'name' => string 'Tsunami' (length=7)
          public 'surname' => string 'Msipha' (length=6)
      2 => 
        object(stdClass)[4]
          public 'name' => string 'Fish' (length=4)
          public 'surname' => string 'Lee' (length=3)

Answer 2

{"data": [{ "name": "Bhengu","surname":"Nathi"}, { "name": "Tsunami","surname":"Msipha"}, { "name": "Fish","surname":"Lee"} ]};

heredata= [ { name: Bhengu, surname: Nathi}, { name: Tsunami, surname: Msipha},{ name: Fish, surname: Lee} ];

您可以使用Json2 script

然后你可以运行：

var myObject = JSON.parse(myJSONtext, reviver);

应该为你提供你需要的数组作为myObject

Answer 3

将json_decode()与第二个参数true一起使用，这将强制将返回的对象转换为数组。

$result = json_decode($jsonStr, true);
if (isset($result)) {
  do something here...
}

检查manual条目是否详细使用（例如$depth参数）。

从JSON转换为数组

3 个答案: