我有这种格式的数组。
Array
(
[0] => Array
(
[0] => User Name
[1] => User Email
[2] => User Mobile
)
[1] => Array
(
[0] => Anjali
[1] => anjali@gmail.com
[2] => 9945587526
)
)
我正在寻找一个json
{"1":"user name","2":"user email","3":"user mobile"}
答案 0 :(得分:3)
您正在寻找json_encode
返回包含值的JSON表示的字符串。
echo json_encode($array);
php>中也提供了json_encode
{} 5.2.0 强>
你也可以试试这个:
$json = array2json($data);
另请注意,JSON中的Array只是索引数组,而PHP Associatives数组是JSON中的对象
答案 1 :(得分:3)
您需要json_encode,但要包含数组的键,您需要设置JSON_FORCE_OBJECT
选项(在PHP> = 5.3.0中可用)。
echo json_encode($arr, JSON_FORCE_OBJECT);
答案 2 :(得分:1)
答案 3 :(得分:1)
<?php
$your_array = array(
0 => array(
0 => "your name",
1 => "your email",
2 => "your mobile"
),
1 => array(
0 => "Anjali",
1 => "Anjali@gmail.com",
2 => "999999999"
)
);
foreach($your_array as $key=>$arr)
{
$arr_temp = array();
$i=0;
foreach($arr as $k=>$v)
{
$i+=1;
$arr_temp[$i] = $v;
}
echo json_encode($arr_temp);
echo "<br/>";
}
?>
OUPUPT:
{"1":"your name","2":"your email","3":"your mobile"}
{"1":"Anjali","2":"Anjali@gmail.com","3":"999999999"}
<强> WORKING DEMO 强>