我试图从我的user_log表中获取一天中的第一个人(标记为user_log.userlog_log_type = 1)和最后一个人(log_type = 2)。在用户中,我有user_id pk和user_name,在user_log中,我在第一个表中有user_id_id_id用于user_id。
现在我设法获得每天的第一个条目以及每天的最后一个条目。但是当我使用内部联接来获取我想要的表(day,firstIn,lastOut)时,我收到错误并且似乎无法找到我做错的事情:
如果有人可以提供帮助,我会非常感激。非常感谢!
答案 0 :(得分:1)
看起来你要经历很多事情才能得到一点...我会从一个单一的查询开始,每天获得最小和最大的人,然后从那里开始。我想要一个用户日志时间戳的索引...
select
LogInOut.LogActivity,
LogInOut.JustDay,
LogInOut.What_Time,
ULMain.UserLog_User_ID,
U1.user_name
from
( select
day( UL.UserLog_Timestamp ) as JustDay,
max( UL.UserLog_Log_type ) as LogActivity,
min( UL.userlog_timestamp ) as What_Time
from
UserLog UL
where
UL.UserLog_Log_Type = 1
group by
day( UL.UserLog_Timestamp )
UNION
select
day( UL.UserLog_Timestamp ) as JustDay,
max( UL.UserLog_Log_type ) as LogActivity,
max( UL.userlog_timestamp ) as What_Time
from
UserLog UL
where
UL.UserLog_Log_Type = 2
group by
day( UL.UserLog_Timestamp ) ) LogInOut
JOIN UserLog ULMain
on LogInOut.What_Time = ULMain.UserLog_Timestamp
AND LogInOut.LogActivity = ULMain.UsrLog_Log_Type
JOIN Users U1
on ULMain.UserLog_User_ID = U1.User_ID
order by
LogInOut.JustDay,
LogInOut.LogActivity
会创建像
这样的东西LogActivity JustDay What_Time UserLog_User_ID user_name
1 Mar 1 7:56am 123 Bill Board
2 Mar 1 6:23pm 431 Eilean Dover
1 Mar 2 7:02am 98 Crystal Clear
2 Mar 2 6:47pm 221 Ben Dover
现在,如果你希望这个汇总到一行(交叉表),那么一行显示那一天,谁在第一个,谁最后,我将换行顶部并添加一个类似的东西
select
LogInOut.JustDay,
MIN( LogInOut.What_Time ) as EarlyLogin,
MAX( IF( LogInOut.LogActivity = 1, U1.User_Name, ' ' )) as EarlyUser,
MAX( LogInOut.What_Time ) as LastLogOut
MAX( IF( LogInOut.LogActivity = 2, U1.User_Name, ' ' )) as LastUser
from
(exact rest of from / join / order by clause)
group by
LogInOut.JustDay
JustDay EarlyLogin EarlyUser LastLogOut LastUser
Mar 1 7:56am Bill Board 6:23pm Eilean Dover
Mar 2 7:02am Crystal Clear 6:47pm Ben Dover