我有两个表,一个名为包含电子邮件(主键)和证书的StudentCerts,另一个名为CertReqs,包含证书和课程。表的一部分看起来像这样:
StudentCerts: CertReqs:
Email Certificate Certificate Course
This@that.com Programmer Programmer CS 101
This@that.com English Programmer CS 202
A@B.com Econ Programmer CS 303
john@smith.com Programmer English ENG 101
English ENG 102
Econ ECON 102
Econ ECON 304
Art Art 101
Art Art 102
Journalism J 101
Journalism J 202
我要做的是获取特定学生不属于的所有证书。例如,This@that.com注册了程序员和英语证书。我想得到一个SQL语句,它将返回CertReqs中特定学生未注册的所有证书。所以对于这个例子它应该归还经济,艺术和新闻。 我一直在努力争取这个,所以任何帮助都会非常感激!!
答案 0 :(得分:2)
SELECT cr.Certificate FROM CertReqs cr
WHERE cr.Certificate NOT IN (
SELECT sc.Certificate FROM StudentCerts sc
WHERE sc.Email = 'This@that.com'
);
该查询几乎可以作为要求:“我想要所有CertReqs,学生不在其中”。
答案 1 :(得分:1)
游戏稍晚,但简单的LEFT JOIN
很好地解决了这个问题:
SELECT DISTINCT cr.Certificate
FROM CertReqs cr
LEFT JOIN StudentCerts sc ON cr.Certificate = sc.Certificate AND sc.Email = 'This@that.com'
WHERE sc.Email IS NULL
答案 2 :(得分:0)
这将列出所有缺少某个证书的学生
SELECT DISTINCT x.*
FROM
(
SELECT a.Email, b.Certificate
FROM (SELECT DISTINCT Email FROM StudentCerts) a
CROSS JOIN
(SELECT DISTINCT Certificate FROM CertReqs) b
) x LEFT JOIN studentCerts y
ON x.Email = y.Email AND
x.Certificate = y.Certificate
WHERE y.Email IS NULL
ORDER BY x.EMAIL
如果您想要特定的电子邮件,那么您只需要添加额外的条件
SELECT DISTINCT x.*
FROM
(
SELECT a.Email, b.Certificate
FROM (SELECT DISTINCT Email FROM StudentCerts) a
CROSS JOIN
(SELECT DISTINCT Certificate FROM CertReqs) b
) x LEFT JOIN studentCerts y
ON x.Email = y.Email AND
x.Certificate = y.Certificate
WHERE y.Email IS NULL AND
x.Email = 'This@that.com'
ORDER BY x.EMAIL
答案 3 :(得分:0)
SELECT Certificate FROM `CertReqs`
WHERE Certificate NOT in(
SELECT Certificate
FROM `StudentCerts`
WHERE Email = 'This@that.com'
)
答案 4 :(得分:0)
SELECT DISTINCT A.* fROM
(
SELECT DISTINCT EMAIL, CERTIFICATE fROM #StudentCerts A
CROSS JOIN #CertReqs B) A
LEFT JOIN #StudentCerts B ON A.EmaiL = B.EMAIL AND B.CERTIFICATES = A.Certificate
WHERE B.EMAIL IS NULL
ORDER BY A.EMAIL