Question

请帮助，因为我花了两天时间......

我有一个JSON对象。如下所示。

[{"attr":{"id":"node_8","rel":"folder"},"data":"_demo","state":"closed"},{"attr":        {"id":"node_13","rel":"folder"},"data":"demo3","state":""}][{"attr":{"id":"node_8","rel":"folder"},"data":"_demo","state":"closed"},{"attr":{"id":"node_13","rel":"folder"},"data":"demo3","state":""}]string(140) "[{"attr":{"id":"node_8","rel":"folder"},"data":"_demo","state":"closed"},{"attr":{"id":"node_13","rel":"folder"},"data":"demo3","state":""}]"

使用Json解码我得到以下输出..

Array ( [0] => Array ( [attr] => Array ( [id] => node_8 [rel] => folder ) [data] => _demo [state] => closed ) [1] => Array ( [attr] => Array ( [id] => node_13 [rel] => folder ) [data] => demo3 [state] => ) ) aArray

如何迭代并以列表形式访问每个值，以便添加div类和id。例如[id] =＆gt; node_8。如何访问该值并将其转换为div id =“node_8”或[rel] =＆gt;文件夹，并转换为div class =“folder”。例如，我希望这是有道理的例如

 foreach ($data as $key => $value){
    if(is_array($value)) {
    {

     echo $value . "<br />";
     }
    }
  }

产生id = node_8 rel =文件夹数据= _demo state = closed id = node_13 rel =文件夹数据= demo3 state =

如果有人遇到多维数组问题，并从JSON解码，将div等添加到数组中，我已经添加了以下答案。由Shayan Husaini提供。其中$ string等于数组。

$json_a=json_decode($string,true);
foreach ($json_a as $value) {

回声'
';       echo'id：'。$ value ['attr'] ['id'];       echo'
';        echo'rel：'。$ value ['attr'] ['rel'];        echo'
';        echo'name：'。$ value ['data'];        echo'
';        echo''。$ value ['state'];        echo'';

Answer 1

您的数组是多维数组，因此您需要为子数组定义键以获取值。我希望这会对你有所帮助：

foreach ($data as $value){
       echo 'id: '.$value['attr']['id'];
       echo 'rel: '.$value['attr']['rel'];
       echo 'demo: '.$value['demo'];
       echo 'state: '.$value['state'];
  }

PHP数组和Json解码错误

1 个答案: