Question

那里有很多JSON / PHP / Decode相关帖子......但我在这里苦苦挣扎。我很确定我错误地构建了我的JSON，但我似乎无法看到我的错误。有人可以帮忙吗？

{
"badging": [
    {
        "event": [
            {
                "eventName": "Covent Garden",
                "numberOfRooms": "1",
                "mainLang": "xx",
                "timeZone": "saas"
            }
        ]
    },
    {
        "names": [
            {
                "id": "1",
                "fName": "Daniel",
                "pos": "King"
            },
            {
                "id": "2",
                "fName": "Dasha",
                "pos": "Queen"
            }
        ]
    }
]
}

这是发布到PHP页面并使用json_decode

$json = $_POST['feed'];
$list = json_decode($json, TRUE);

我觉得我应该可以访问以下数据：

echo $list[1][2]['fName'];

或

echo $list->badging[1]->names[2]->fName;

但我似乎无法做到。感谢

Answer 1

应该是：

print($list["badging"][1]["names"][0]["fName"]); // outputs "Daniel"
print($list["badging"][1]["names"][1]["fName"]); // outputs "Dasha"

Answer 2

尝试$list['badging'][1]['names'][1]['fName'];
http://codepad.org/IdneHeDL
此外，如果省略json_decode的true，则$list->badging[1]->names[1]->fName;
http://codepad.org/WXWkVqo1

Answer 3

这就是你的数组的外观。

array(1) {
  ["badging"]=>
  array(2) {
    [0]=>
    array(1) {
      ["event"]=>
      array(1) {
        [0]=>
        array(4) {
          ["eventName"]=>
          string(13) "Covent Garden"
          ["numberOfRooms"]=>
          string(1) "1"
          ["mainLang"]=>
          string(2) "xx"
          ["timeZone"]=>
          string(4) "saas"
        }
      }
    }
    [1]=>
    array(1) {
      ["names"]=>
      array(2) {
        [0]=>
        array(3) {
          ["id"]=>
          string(1) "1"
          ["fName"]=>
          string(6) "Daniel"
          ["pos"]=>
          string(4) "King"
        }
        [1]=>
        array(3) {
          ["id"]=>
          string(1) "2"
          ["fName"]=>
          string(5) "Dasha"
          ["pos"]=>
          string(5) "Queen"
        }
      }
    }
  }
}

例如。 echo $ list ['badging'] [0] ['event'] [0] ['eventName'];

Answer 4

根据您的JSON，通过JSON_decode，我们得到

Array ( [badging] => Array ( [0] => Array ( [event] => Array ( [0] => Array ( [eventName] => Covent Garden [numberOfRooms] => 1 [mainLang] => xx [timeZone] => saas ) ) ) [1] => Array ( [names] => Array ( [0] => Array ( [id] => 1 [fName] => Daniel [pos] => King ) [1] => Array ( [id] => 2 [fName] => Dasha [pos] => Queen ) ) ) ) )

因此，要访问它，您需要使用

echo $list['badging'][1]['names'][0]['fName'];

快乐编码：）

JSON PHP解码数组和对象

4 个答案: