我正在尝试进行查询,其中汇总了每个客户的订单总数。
我尝试过几种不同的方法,但我不确定是否采取正确的方法。
我试过......
SELECT *
FROM Orders
SUM(Total) as Totals
COUNT(OrderID) as OrderAmt
GROUP BY CustomerID, OrderAmt, ShipName, Totals
我想得到这个结果......
=====================================
|CustomerID|Orders |ShipName|Total |
|==========|=======|========|=======|
|3334 |3 |Joe Blow|1100.00|
|----------|-------|--------|-------|
|114 |2 |Steve |280.00 |
|----------|-------|--------|-------|
|1221 |1 |Sue |250.00 |
|----------|-------|--------|-------|
|3444 |1 |Bob |22.00 |
=====================================
从这张表中......
|===================================|
|CustomerID|OrderID|ShipName|Total |
|==========|=======|========|=======|
|3334 |232 |Joe Blow|400.00 |
|----------|-------|--------|-------|
|3334 |234 |Joe Blow|500.00 |
|----------|-------|--------|-------|
|3334 |231 |Joe Blow|200.00 |
|----------|-------|--------|-------|
|114 |235 |Steve |250.00 |
|----------|-------|--------|-------|
|114 |239 |Steve |30.00 |
|----------|-------|--------|-------|
|1221 |244 |Sue |250.00 |
|----------|-------|--------|-------|
|3444 |632 |Bob |22.00 |
|===================================|
对此,正确的SQL语句是什么。
答案 0 :(得分:24)
Sum
和count
可用于获得您想要的结果:
select CustomerID, count(*) as Orders, ShipName, sum(Total) as Total
from Table
group by CustomerID, ShipName
order by count(*) desc;
答案 1 :(得分:2)
select CustomerID, count(OrderID) Orders, ShipName, sum(Total) Total
from Order_TAB
group by CustomerID, ShipName