Question

好的，对于我正在研究的视频游戏的结构，我需要在结构“dungeon”中分配“房间”结构。不幸的是，我似乎无法分配足够的内存来提供我需要的所有信息。以下是我的数据结构示例：

typedef struct monster {
    int difficulty;
    char *name;
    char *type;
    int hp;
} monster;

typedef struct rooms {
    int n_monsters;
    int visited;
    struct rooms *nentry;
    struct rooms *sentry;
    struct rooms *wentry;
    struct rooms *eentry;
    monster *monsters;
} rooms;

typedef struct dungeon {
    char *name;
    int n_rooms;
    rooms *rm; // Subject to change
    rooms sroom;
} dungeon;

这就是我收到分段错误的地方。

d->name = "Dungeon 1";
d->n_rooms = 10;
rooms *room = malloc(d->n_rooms * sizeof(rooms));

// Room 0
room[0].n_monsters = 1;
room[0].visited = 0;
*room[0].sentry = room[1]; // xCode is showing the seg-fault here

// Room 2
room[1].n_monsters = 1;
room[1].visited = 0;
*room[1].nentry = room[0];

d->rm = room;

为什么我会遇到seg-fault？我分配了足够的内存吗？

Answer 1

您没有为room[0].sentry分配内存。尝试：

room[0].sentry = malloc(sizeof *room[0].sentry);
*room[0].sentry = ...

或者，您可以只指定指针（我想如果在您的情况下效果更好）：

room[0].sentry = &room[1];

段错误。在struct中为struct分配内存

1 个答案: