Question

我正在使用带有HTTP Basic Auth的spring-security来保护java webapp。在我的webapp中，我需要获取当前用户的用户名和密码，以进一步针对其他服务进行身份验证。我可以获取用户名，但不能获取密码。

我已尝试使用SecurityContextHolder.getContext().getAuthentication()按照此处How can I get plaintext password from spring-security?的建议访问此信息，但密码将以null的形式返回。

如何获取密码？

感谢。

这是我的applicationContext-security.xml

<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:sec="http://www.springframework.org/schema/security" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/beans
       http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
       http://www.springframework.org/schema/security
       http://www.springframework.org/schema/security/spring-security-3.1.xsd">

<sec:http authentication-manager-ref='authenticationManager'>
    <sec:intercept-url pattern="/spring/**" access="ROLE_USER" />
    <sec:http-basic />
</sec:http>

<bean id="basicAuthenticationFilter"
    class="org.springframework.security.web.authentication.www.BasicAuthenticationFilter">
    <property name="authenticationManager" ref="authenticationManager" />
    <property name="authenticationEntryPoint" ref="authenticationEntryPoint" />
</bean>

<bean id="authenticationEntryPoint"
    class="org.springframework.security.web.authentication.www.BasicAuthenticationEntryPoint">
    <property name="realmName" value="Announcements Rest Realm" />
</bean>

<bean id="authenticationManager"
    class="org.springframework.security.authentication.ProviderManager">
    <property name="providers">
        <list>
            <ref local="authProvider" />
        </list>
    </property>
</bean>

<bean id="authProvider"
    class="org.springframework.security.authentication.dao.DaoAuthenticationProvider">
    <property name="userDetailsService" ref="userDetailsService" />
</bean>

<bean id="filterChainProxy" class="org.springframework.security.web.FilterChainProxy">
    <constructor-arg>
        <list>
            <sec:filter-chain pattern="/spring/**" filters="basicAuthenticationFilter" />
        </list>
    </constructor-arg>
</bean>

<sec:user-service id="userDetailsService">
    <sec:user name="admin" password="**" authorities="ROLE_USER, ROLE_ADMIN" />
    <sec:user name="user" password="**" authorities="ROLE_USER" />
</sec:user-service>

Answer 1

我已经明白了。

我已将身份验证管理器配置更改为使用authentication-manager元素并在其中添加了属性：

<sec:authentication-manager alias="authenticationManager" erase-credentials="false">
    <sec:authentication-provider ref="authProvider" />      
</sec:authentication-manager>

然后我可以在我的控制器类中使用SecurityContextHolder.getContext().getAuthentication().getCredentials()来获取密码。

感谢Piotrek De的帮助

Answer 2

你是否记得我/ run as / switch用户？在这种情况下，密码为空（如您提到的主题中所述）。此外，您可能必须使用基本表单身份验证，（向j_spring_security_check发送请求）

Answer 3

如果要设置当前用户的全部详细信息，包括会话对象中的密码，则可以从该会话对象中获取密码。

Answer 4

更好的方法是实现'userDetailsService'。因此，您可以控制在进行身份验证时如何使用UserDetails。我实现了基于表单的身份验证并编写了我自定义的用户服务

@Service("userService")
public class UserServiceImpl extends GenericService<User> implements UserDetailsService,UserService{



    @Override
        @Transactional
        public UserDetails loadUserByUsername(String username) throws UsernameNotFoundException, DataAccessException {
               // Declare a null Spring User
            UserDetails userDetails = null;



            // Search database for a user that matches the specified username
            // You can provide a custom DAO to access your persistence layer
            // Or use JDBC to access your database
            // DbUser is our custom domain user. This is not the same as Spring's User
            User dbUser=this.findUserByUserName(username);

            if (dbUser == null) {
                throw new UsernameNotFoundException("HiMVC Security:: Error in retrieving user(username=" + username + ")");
            }



            userDetails = new org.springframework.security.core.userdetails.User(
                    dbUser.getUserName(),
                    dbUser.getPassword(),//here you can put a clear text password
                    true,
                    true,
                    true,
                    true,
                    loadUserAuthorities(username));


            return userDetails;
        }

从spring-security检索当前用户的密码

4 个答案: