我正在使用LDAP身份验证提供程序(活动目录)+ JWT授权过滤器。
我有实现UserDetails
的自定义用户对象,我的用户服务也扩展了UserDetailsService
。但是当我这样做时:
Usuario principal = (Usuario) SecurityContextHolder.getContext().getAuthentication().getPrincipal();
Principal
只是一个字符串(用户名),而不是我的用户对象。
这是我的配置:
SecurityConfig:
@Configuration
@EnableWebSecurity
public class SecurityConfig extends WebSecurityConfigurerAdapter {
private final LdapProperties ldapProperties;
private final LdapUserMapper ldapUserMapper;
private final UserService userService;
public SecurityConfig(LdapProperties ldapProperties, LdapUserMapper ldapUserMapper, UserService userService) {
this.ldapProperties = ldapProperties;
this.ldapUserMapper = ldapUserMapper;
this.userService = userService;
}
@Override
protected void configure(HttpSecurity http) throws Exception {
// Entry points
http.authorizeRequests()
.antMatchers(HttpMethod.POST, "/login").permitAll()
.antMatchers(HttpMethod.GET, "/v2/api-docs",
"/configuration/ui",
"/swagger-resources",
"/configuration/security",
"/swagger-ui.html",
"/webjars/**",
"/swagger-resources/**",
"/swagger-ui.html").permitAll()
//TODO review
.anyRequest().authenticated();
// JwtWebSecurityConfigurer... TODO ?
// Filters
http.addFilter(new AuthenticationFilter(authenticationManager())); // ldap
http.addFilter(new AuthorizationFilter(authenticationManager())); // jwt
http.cors();
http.csrf().disable();
// No session will be created or used by spring security
http.sessionManagement().sessionCreationPolicy(SessionCreationPolicy.STATELESS);
// Need to provide Authorization header
http.httpBasic();
}
@Override
public void configure(AuthenticationManagerBuilder auth) throws Exception {
auth.authenticationProvider(ldapAuthenticationProvider());
auth.userDetailsService(userService);
}
@Bean
public CorsConfigurationSource corsConfigurationSource() {
CorsConfiguration corsConfiguration = new CorsConfiguration().applyPermitDefaultValues();
corsConfiguration.setAllowedMethods(Arrays.asList(CorsConfiguration.ALL));
//TODO configure properly
final UrlBasedCorsConfigurationSource source = new UrlBasedCorsConfigurationSource();
source.registerCorsConfiguration("/**", corsConfiguration);
return source;
}
@Bean
public AbstractLdapAuthenticationProvider ldapAuthenticationProvider() {
String urls = "";
for (String url : ldapProperties.getUrls()) {
urls += url + " ";
}
urls = urls.trim();
ActiveDirectoryLdapAuthenticationProvider provider = new ActiveDirectoryLdapAuthenticationProvider(
ldapProperties.getBaseEnvironment().get("domain"),
urls,
ldapProperties.getBase()
);
provider.setUserDetailsContextMapper(ldapUserMapper);
provider.setConvertSubErrorCodesToExceptions(true);
// comment to connect as anonymous
provider.authenticate(
new UsernamePasswordAuthenticationToken(ldapProperties.getUsername(), ldapProperties.getPassword())
);
return provider;
}
}
LdapUserMapper:
@Component
public class LdapUserMapper implements UserDetailsContextMapper {
private final UserService userService;
@Autowired
public LdapUserMapper(UserService userService) {
this.userService = userService;
}
@Override
public UserDetails mapUserFromContext(DirContextOperations ctx, String username, Collection<? extends GrantedAuthority> authorities) {
Usuario result = (Usuario) userService.loadUserByUsername(username);
//TODO compare roles ? set bloqueado ? ...
return result;
}
@Override
public void mapUserToContext(UserDetails userDetails, DirContextAdapter dirContextAdapter) {
}
}
答案 0 :(得分:0)
这是我的授权过滤器。
@Override
protected void doFilterInternal(HttpServletRequest req,
HttpServletResponse res,
FilterChain chain) throws IOException, ServletException {
String token = req.getHeader("Authorization");
if (token != null && token.startsWith("Bearer ")) {
token = token.replace("Bearer ", "");
Authentication authentication = getAuthentication(token);
SecurityContextHolder.getContext().setAuthentication(authentication);
}
chain.doFilter(req, res);
}
private UsernamePasswordAuthenticationToken getAuthentication(final String token) {
try {
DecodedJWT decodedToken = JWT.require(Algorithm.HMAC512(jwtSecret)).build().verify(token);
String username = decodedToken.getSubject();
return new UsernamePasswordAuthenticationToken(username , null, new ArrayList<>());
} catch (JWTVerificationException ex) {
log.error(ex.getMessage());
}
return null;
}
我不知道我只是将用户名作为Principal
对象传递。所以我将其更改为:
Usuario usuario = (Usuario) userService.loadUserByUsername(decodedToken.getSubject());
我也删除了
auth.userDetailsService(userService);
来自AuthenticationManagerBuilder
配置。错了我的身份验证提供程序是LDAP,而不是数据库。