我想显示联系人的电话号码。如果我在模拟器中运行我的代码没有任何反应,但是当我在我的SmartPhone中运行它时,我在logcat中发现了这个错误---->
android.database.CursorIndexOutOfBoundsException: Index 0 requested, with a size of 0
我正在使用的代码是
Cursor peopleCursor =
getContentResolver().query(ContactsContract.Contacts.CONTENT_URI
,null, null,null, null);
String [] nb = new String[peopleCursor.getCount()];
String [] Tname = new String[peopleCursor.getCount()];
if(peopleCursor.getCount()>0){
peopleCursor.moveToFirst();
Cursor numberCursor;
for(int i=0;i<peopleCursor.getCount();i++)
{
//get number
numberCursor=
getContentResolver().query(ContactsContract.
CommonDataKinds.Phone.CONTENT_URI, new String[]
{ContactsContract.CommonDataKinds.Phone.NUMBER}
,ContactsContract.CommonDataKinds.Phone._ID+"="+peopleCursor
.getString(peopleCursor.getColumnIndex(ContactsContract.Contacts._ID))
, null,null);
numberCursor.moveToFirst();
String number=numberCursor.getString(numberCursor
.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
nb[i]=number;
//get name
String name=peopleCursor.getString(numberCursor
.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME));
Tname[i]=name;
peopleCursor.moveToNext();
}
SimpleCursorAdapter adapter = new SimpleCursorAdapter(this,
R.layout.contact_entry, peopleCursor,nb
, new int[] {R.id.checkBox});
lv.setAdapter(adapter);
}
}
请问任何解决方案?
答案 0 :(得分:0)
几乎可以肯定的是,您的联系人数据库中有一些没有电话号码的条目。您的代码似乎没有考虑到这一点。在访问numberCursor
之前检查numberCursor.moveToFirst()
的返回值
答案 1 :(得分:0)
如果你想使用SimpleCursorAdapter,我也不能帮助你,因为我也是新手,但是下面的代码应该给你正确的语音。
可能不是您正在寻找的确切答案,但如果联系人有一个,它会为您提供每个联系人的电话号码:
//Initialize Adapter
ArrayAdapter<String> adapter = new ArrayAdapter<String>(mContext, android.R.layout.simple_list_item_1);
//Get List of all COntacts
Uri uri = ContactsContract.Data.CONTENT_URI;
String columns[] = {
ContactsContract.Contacts.DISPLAY_NAME,
ContactsContract.Contacts.HAS_PHONE_NUMBER,
ContactsContract.CommonDataKinds.Phone.CONTACT_ID,
};
Cursor contactCursor = mContext.getContentResolver().query(
uri,
columns,
null,
null,
null
);
//For every Rsult do this
while (contactCursor.moveToNext()) {
String phoneNO = "";
String name = contactCursor.getString(contactCursor.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME));
String id = contactCursor.getString(contactCursor.getColumnIndex(ContactsContract.CommonDataKinds.Phone.CONTACT_ID));
//Check if COntact has a phone number
if (Integer.parseInt(contactCursor.getString(contactCursor.getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER))) > 0){
//Create Cursor to get Phone Number (You need the Phone.Contact_ID here)
Cursor numberCursor = mContext.getContentResolver().query(
ContactsContract.CommonDataKinds.Phone.CONTENT_URI,
new String[]{ContactsContract.CommonDataKinds.Phone.NUMBER},
ContactsContract.CommonDataKinds.Phone.CONTACT_ID + " = ?",
new String[]{id},
null,
null
);
if (numberCursor.moveToFirst()){
phoneNO = numberCursor.getString(numberCursor.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
}
}
//Create String you want to show in List
String contactList = "name: " + name + " Phonenumber: " + phoneNO;
adapter.add(contactList);
}
listView.setAdapter(adapter);
也许这个答案可以帮到你: How to get contacts' phone number in Android
小心:代码只返回给你一个联系人的第一个phonenumber