Question

我有一个应用程序，其中一个方面是供用户选择联系人并通过应用程序向该联系人发送文本。该应用程序仅适用于某些联系人，而其他联系人则失败更确切地说：

对于我手动输入联系人联系人的联系人，Intent.ACTION_PICK可以轻松找到并将其返回给应用，即cursor.moveToFirst()为真。

但是对于Facebook导入的联系人（我的手机设置为与Facebook联系人同步），我点击联系人后会得到以下android.database.CursorIndexOutOfBoundsException。我有一个明显的问题是：在我真正选择了一个联系人后，为什么结果大小为0？为什么cursor.moveToFirst()为假？

...Caused by: android.database.CursorIndexOutOfBoundsException: Index 0 requested, with a size of 0
05-15 17:57:04.741: E/AndroidRuntime(21301):    at android.database.AbstractCursor.checkPosition(AbstractCursor.java:418)
05-15 17:57:04.741: E/AndroidRuntime(21301):    at android.database.AbstractWindowedCursor.checkPosition(AbstractWindowedCursor.java:136)
05-15 17:57:04.741: E/AndroidRuntime(21301):    at android.database.AbstractWindowedCursor.getString(AbstractWindowedCursor.java:50)
05-15 17:57:04.741: E/AndroidRuntime(21301):    at android.database.CursorWrapper.getString(CursorWrapper.java:114)
05-15 17:57:04.741: E/AndroidRuntime(21301):    at com.company.Game.SendTextActivity.onActivityResult(SendTextActivity.java:118)
05-15 17:57:04.741: E/AndroidRuntime(21301):    at android.app.Activity.dispatchActivityResult(Activity.java:5436)
05-15 17:57:04.741: E/AndroidRuntime(21301):    at android.app.ActivityThread.deliverResults(ActivityThread.java:3188)
05-15 17:57:04.741: E/AndroidRuntime(21301):    ... 11 more

这是我的代码：

dispatchIntent：

Intent pickContactIntent = new Intent(Intent.ACTION_PICK,  Uri.parse("content://contacts"));
pickContactIntent.setType(Phone.CONTENT_TYPE); // Show user only contacts w/ phone numbers
    startActivityForResult(pickContactIntent, PICK_CONTACT_REQUEST);

onActivity结果：

(requestCode == PICK_CONTACT_REQUEST) {
            // Get the URI that points to the selected contact
            Uri contactUri = data.getData();
            // We only need the NUMBER column, because there will be only one row in the result
            String[] projection = { Phone.NUMBER };

            // Perform the query on the contact to get the NUMBER column
            // We don't need a selection or sort order (there's only one result for the given URI)
            // CAUTION: The query() method should be called from a separate thread to avoid blocking
            // your app's UI thread. (For simplicity of the sample, this code doesn't do that.)
            // Consider using CursorLoader to perform the query.
            Cursor cursor = getContentResolver()
                .query(contactUri, projection, null, null, null);
            cursor.moveToFirst();

            // Retrieve the phone number from the NUMBER column
            int column = cursor.getColumnIndex(Phone.NUMBER);
            String number = cursor.getString(column);

            //do work with number here ...
        }

注意：我看到了联系人。但是在我选择了Facebook导入的联系人之后，我就崩溃了。

BTW：我的代码片段完全是从Android教程中复制的：http://developer.android.com/training/basics/intents/result.html

Answer 1

您无法通过Contacts API访问FB联系人。

Answer 2

要修复崩溃，你应该像这样检查moveToFirst（）的结果：

String number = null;
if (cursor.moveToFirst()) {
   number = cursor.getString(0); // 0 matches the index of NUMBER in your projection.
}

为了探索可用的数据的性质，我将为投影传递“null”，以便所有字段都返回，并转储字段名称和值。您可以找到您要查找的数据，而不是在NUMBER字段中。

Intent.ACTION_PICK为某些联系人返回空光标

2 个答案: