Question

在C＃中，我如何设置2个字节，前10位代表一个十进制值，接下来的6代表不同的十进制值？

因此，如果第一个值为'8'（前10位），第二个'2'（剩余6位），我需要在字节数组中最后得到'0000001000 000010'。

谢谢！广告

Answer 1

UInt16 val1 = 8;
UInt16 val2 = 2;
UInt16 combined = (UInt16)((val1 << 6) | val2);

如果在字节数组中需要它，可以将结果传递给BitConverter.GetBytes method。

byte[] array = BitConverter.GetBytes(combined);

Answer 2

int val1 = 8;
int val2 = 2;

// First byte contains all but the 2 least significant bits from the first value.
byte byte1 = (byte)(val1 >> 2);

// Second byte contains the 2 least significant bits from the first value,
// shifted 6 bits left to become the 2 most significant bits of the byte,
// followed by the (at most 6) bits of the second value.
byte byte2 = (byte)((val1 & 4) << 6 | val2);

byte[] bytes = new byte[] { byte1, byte2 };

// Just for verification.
string s =
    Convert.ToString(byte1, 2).PadLeft(8, '0') + " " +
    Convert.ToString(byte2, 2).PadLeft(8, '0');

Answer 3

不考虑任何类型的溢出：

private static byte[] amend(int a, int b)
{
    // Combine the datum into a 16 bits integer
    var c = (ushort) ((a << 6) | (b));
    // Fragment the Int to bytes
    var ret = new byte[2];
    ret[0] = (byte) (c >> 8);
    ret[1] = (byte) (c);

    return ret;
}

Answer 4

ushort value = (8 << 6) | 2;
byte[] bytes = BitConverter.GetBytes(value);

修改10位2字节

4 个答案: