我无法理解Foo
移动构造函数在以下示例中尝试调用~ptr
的原因:
#include <utility>
template <typename T, typename Policy>
class ptr {
T * m_t;
public:
ptr() noexcept : m_t(0) {}
explicit ptr(T *t) noexcept : m_t(t) {}
ptr(const ptr &other) noexcept : m_t(Policy::clone(other.m_t)) {}
ptr(ptr &&other) noexcept : m_t(other.m_t) { other.m_t = 0; }
~ptr() noexcept { Policy::delete_(m_t); }
ptr &operator=(const ptr &other) noexcept
{ ptr copy(other); swap(copy); return *this; }
ptr &operator=(ptr &&other) noexcept
{ std::swap(m_t,other.m_t); return *this; }
void swap(ptr &other) noexcept { std::swap(m_t, other.m_t); }
const T * get() const noexcept { return m_t; }
T * get() noexcept { return m_t; }
};
class FooPolicy;
class FooPrivate;
class Foo {
// some form of pImpl:
typedef ptr<FooPrivate,FooPolicy> DataPtr;
DataPtr d;
public:
// copy semantics: out-of-line
Foo();
Foo(const Foo &other);
Foo &operator=(const Foo &other);
~Foo();
// move semantics: inlined
Foo(Foo &&other) noexcept
: d(std::move(other.d)) {} // l.35 ERR: using FooDeleter in ~ptr required from here
Foo &operator=(Foo &&other) noexcept
{ d.swap(other.d); return *this; }
};
GCC 4.7:
foo.h: In instantiation of ‘ptr<T, Policy>::~ptr() [with T = FooPrivate; Policy = FooPolicy]’:
foo.h:34:44: required from here
foo.h:11:14: error: incomplete type ‘FooPolicy’ used in nested name specifier
Clang 3.1-pre:
foo.h:11:14: error: incomplete type 'FooPolicy' named in nested name specifier
~ptr() { Policy::delete_(m_t); }
^~~~~~~~
foo.h:34:5: note: in instantiation of member function 'ptr<FooPrivate, FooPolicy>::~ptr' requested here
Foo(Foo &&other) : d(std::move(other.d)) {}
^
foo.h:23:7: note: forward declaration of 'FooPolicy'
class FooPolicy;
^
foo.h:11:20: error: incomplete definition of type 'FooPolicy'
~ptr() { Policy::delete_(m_t); }
~~~~~~^~
2 errors generated.
发生了什么事?我正在编写移动构造函数以避免运行复制ctors和dtors。请注意,这是一个试图隐藏其实现的头文件(pimpl idiom),因此不能选择使用FooDeleter
完整类型。
编辑:在Bo的回答之后,我尽可能地添加了noexcept
(在上面编辑过)。但错误仍然是一样的。
答案 0 :(得分:9)
您创建一个包含Foo
成员的新ptr<something>
对象。如果Foo
构造函数失败,编译器必须为部分构造的Foo
的任何完全构造的成员调用析构函数。
但它无法实例化~ptr<incomplete_type>()
,因此失败。
你有一个类似的私有析构函数的情况。这也阻止您创建该类型的对象(除非从朋友或成员函数完成)。