不要在匹配中包含字符串

Question

我正在尝试在类似

的字符串上运行正则表达式

string = 'The value is ij35dss. The value is fsd53fdsfds.'

我想要的地方string.match(/The value is (.*?)\./g);  仅返回['ijdss','fsdfdsfds']而非['The value is ijdss.', 'The value is fsdfdsfds.']

Answer 1

使用RegExp.exec代替，这是一个示例：

var string = 'The value is ij35dss. The value is fsd53fdsfds.';
var re = new RegExp(/The value is (.*?)\./g)

var strs = []   
var m = re.exec(string)

while(m != null) {
  strs.push(m[1]);
  m = re.exec(string)
}

alert(strs)

和jsFiddle：

• http://jsfiddle.net/WtTPd/

如果您认为经常需要这个，可以将其添加到String.prototype：

String.prototype.matchGroup = function(re, group) {
  var m = re.exec(string);
  var strs = [];
  while(m != null) {
    strs.push(m[group]);
    m = re.exec(string);
  }
  return strs;
}

var string = 'The value is ij35dss. The value is fsd53fdsfds.';
alert(string.matchGroup(/The value is (.*?)\./g, 1));

的jsfiddle：

• http://jsfiddle.net/WtTPd/1/

现金：

• How do you access the matched groups in a JavaScript regular expression?