如何在CodeIgniter中执行此查询

时间:2012-02-21 13:11:57

标签: php ajax codeigniter

这是控制器方法

public function ajaxLoad()
{
    $data['query'] = $this->db->query("SELECT * FROM items ORDER BY id DESC");
    $data['content'] = $this->load->view('item', $data, true);
    $data = json_encode($data);
    echo $data;
}

这是调用ajax

的js
var tempScrollTop, currentScrollTop = 0; 
$(document).scroll(function(){ 

currentScrollTop = $(document).scrollTop(); 

if (tempScrollTop < currentScrollTop ) 
{
    var result = currentScrollTop % 100;
    if(result == 0)
    {
        $.ajax({
          url: "ajax/load",
          type: "POST",
          success: function(res){

          $("#content").html(res);

          }
        });
    }
}
else if (tempScrollTop > currentScrollTop ) 
{
    var result = currentScrollTop % 100;
    if(result == 0)
    {
        $("#content").text("Вверх запрос " + result);
    }
}

tempScrollTop = currentScrollTop; 
})

问题我无法获取内容中的查询页面的一部分然后json_encode转移到javascript,如果我删除

 $data['query'] = $this->db->query("SELECT * FROM items ORDER BY id DESC");

并将其更改为

$data['content'] = $this->load->view('item', null, true);

因此没有$ data对象就可以了。

然后它变空了,但我需要在内容中显示数据库行

我该如何解决这个问题?

和echo $ data; - 它是将数据传输到js ??的唯一方法,我尝试返回$ data;,但这不起作用:(

并且主要的问题是PHP生成带有foreach函数的页面,该函数通过循环生成记录,但是如果我将其中一个记录与ajax放在一起,那部分内的变量将成为数据库查询的值??,或者我需要用js ??

设置值 我很困惑,对不起,如果我错了,你能帮助我吗?

所以这就是如何在页面加载时查看php生成的页面:

<? $i = 1 ?>
<? foreach($query->result() as $q): ?>



<?
$milliseconds = $q->end;
//echo $dd;
//echo time();
 /*
$year = date('y', $t);
$month = date('m', $t);
$day = date('d', $t);
$hour = date('h', $t);
$minute = date('i', $t);
$second = date('s', $t);
*/
$d = new Datecalc;
$begin = date("Y-m-d H:i:s");
$end = date($q->end);
#$date = $d->dateDiff($begin , $end);
//$begin = strtotime($begin);
//$end = strtotime($q->end);
$d->dateDiff($begin, $end);
//echo $d->day;

$desc = substr($q->desc, 0, 225);
if(strlen($desc) > 180)
{
    $desc = $desc."...";
}
 ?>
<input type="hidden" value="<?= $milliseconds ?>" id="milliseconds_<?= $q->id ?>" />
<div class="item" id="item_<?= $q->id ?>">
        <? if(!empty($_SESSION['role']) && $_SESSION['role'] == 'admin'): ?>
        <div class="admin_delete">
        <a href="<?= base_url() ?>delete/<?= $q->id ?>"><?= img('css/img/admin_delete.png'); ?></a>
        </div>

        <? endif; ?>
    <div class="desc">
    <span class="discount">Скидка <?= $q->discount ?>%</span>
    <span class="desc"><?= $desc ?></span>
    </div>
    <div class="item_pic">
    <? $attr = array('src' => $q->image,
    'id' => 'item_pic',
    'class' => 'item_pic') ?>
    <?= img($attr) ?>
    </div>
    <div class="menu_3">
        <ul class="menu_3">
            <li class="timer">
            <? $attr = array('src' => 'css/img/time.png',
            'class' => 'time') ?>
            <?= img($attr) ?>
            <span id="days_<?= $q->id?>"><?= $d->day ?></span>д.
            <span  id="hours_<?= $q->id?>"><?= $d->hour ?></span> :
            <span  id="minutes_<?= $q->id?>"><?= $d->min ?></span> :
            <span  id="seconds_<?= $q->id?>"><?= $d->sec ?></span>
            </li>
            <li class="price">
            <?= $q->price ?>с.
            </li>
            <li class="buy">
            <div class="small">
            99
            </div>
            <a href="<?= base_url() ?>buy/<?= $q->id ?>">
            <?= img('css/img/kupit.png') ?>
            </li>
            <li class="item_arrow">
            <?= img('css/img/item_arrow.png') ?>
            <? if($i % 2 == 0): ?>
                <ul class="submenu2">
                <? else: ?>
                <ul class="submenu2">
            <? endif; ?>
                    <li>
                    <a href="<?= base_url() ?>show/<?= $q->id ?>">
                    Подробнее
                    </a>
                    </li>
                    <li>
                    <a href="<?= base_url() ?>how" style="color: #fef102;">Как это работает</a>
                    </li>
                    <li style="border-bottom: none;">
                    <a href="">Рассказать друзьям</a>
                    </li>
                    <li style="border-bottom: none;">
                    <a href=""><?= img('css/img/namba.png') ?></a>
                    <a href=""><?= img('css/img/mail_ru.png') ?></a>
                    <a href=""><?= img('css/img/odnoklassniki.png') ?></a>
                    <a href=""><?= img('css/img/vkontakte.png') ?></a>
                    <a href=""><?= img('css/img/facebook.png') ?></a>
                    </li>
                </ul>
            </li>
        </ul>
    </div>
    </div>
<? $i++; ?>
<? endforeach; ?>
    <div class="clear"></div>

当用户向下滚动

时,我不知道如何通过ajax分别逐渐放置记录

1 个答案:

答案 0 :(得分:1)

尝试重写这两行

$data['query'] = $this->db->query("SELECT * FROM items ORDER BY id DESC");
$data['content'] = $this->load->view('item', $data, true);

作为

$db_data['query'] = $this->db->query("SELECT * FROM items ORDER BY id DESC");
$data['content'] = $this->load->view('item', $db_data, true);

实际上,作为JSON输出的一部分,您将从DB(在$ data数组中)发送查询响应。然后用

替换最后两行
echo json_encode($data);