我有两张桌子:
表1:
name added_by edited_by
a 1 3
b 2 2
c 3 1
表2:
id login
1 admin
2 user1
3 user2
我需要这个结果:
name added_by edited_by
a admin user2
b user1 user1
c user2 admin
答案 0 :(得分:2)
您可以尝试此查询
ContentValues values = new ContentValues();
values.put(DogEntry.NAME, "Doggy");
values.put(DogEntry.BREED, "Dingo");
values.put(DogEntry.GENDER, DogEntry.GENDER_MALE);
values.put(DogEntry.WEIGHT, 15);
Uri newUri = getContentResolver().insert(DogEntry.CONTENT_URI,values);