Question

声明：“已购买全系列许可证的客户”

表：

SERIES:
title           
total_seasons

SEASONS:
title           
season      
avgduration 
episodes 
PRIMARY KEY (title, season),
FOREIGN KEY (title) REFERENCES SERIES

LIC_SERIES:
id_client
datetime
title
season
episode 
PRIMARY KEY (client,title,season,episode)
FOREIGN KEY (title,season) REFERENCES seasons

系列示例如下所示：

Title     Total_Seasons
House     8
Lost      6

季节示例如下所示：

Title    Season AvgDuration Episodes
House    1      44          22
Mad Men  3      47          13

Lic_Series示例如下所示：

Client   Datetime   Title Season Episode
92/657/T 01/01/2017 House 8      18

我尝试了什么？

WITH PART AS (SELECT DISTINCT EPISODES, TITLE
FROM SEASONS INNER JOIN SERIES
ON Seasons.Title = Series.Title
GROUP BY Seasons.Title)

SELECT CLIENT 
FROM LIC_SERIES INNER JOIN PART
ON LIC_SERIES.TITLE = PART.TITLE
ORDER BY title DESC;

我不知道如何检查客户是否有每季的所有剧集，以及该系列剧的所有季节

Answer 1

这将返回每个季节拥有且不属于每个客户的剧集数量。要检查是否拥有所有剧集，请对episodes_not_owned为零的摘要进行额外检查

WITH PART AS 
(SELECT DISTINCT s2.TITLE, s1.SEASON, s2.EPISODE
FROM SEASONS s1
INNER JOIN SERIES s2
ON s1.Title = s2.Title
)
,summary as (
SELECT l.CLIENT
      ,p.SEASON
      ,SUM(CASE WHEN l.episode is not null THEN 1 ELSE NULL END) as episodes_owned
      ,SUM(CASE WHEN l.episode is null THEN 1 ELSE NULL END) as episodes_not_owned
FROM LIC_SERIES l
RIGHT OUTER JOIN PART p
ON l.TITLE = p.TITLE
AND l.EPISODE = p.EPISODE
AND l.SEASON = p.SEASON
GROUP BY l.CLIENT, p.SEASON
ORDER BY l.CLIENT, p.SEASON DESC
)
SELECT s.client
      ,s.season
      ,s.episodes_owned
      ,s.episodes_not_owned
      ,case when s.episodes_not_owned = 0 THEN 'Yes' ELSE 'No' END as all_owned
from summary s;

我怎么能这样做oracle查询

1 个答案: