我尝试从使用PasswordText WSS类型的Web服务获取信息。首先,我使用soapUI测试它并成功获取数据。然后我在Java上实现了身份验证,编写了SecurityHandler:
public final class SecurityHandler implements SOAPHandler<SOAPMessageContext> {
...
@Override
public boolean handleMessage(SOAPMessageContext messageContext) {
boolean outInd = (Boolean) messageContext.get(MessageContext.MESSAGE_OUTBOUND_PROPERTY);
if (outInd) {
try {
WSSecUsernameToken builder = new WSSecUsernameToken();
builder.setPasswordType(WSConstants.PASSWORD_TEXT);
builder.setUserInfo(_username, _password);
builder.addNonce();
builder.addCreated();
Document doc = messageContext.getMessage().getSOAPPart().getEnvelope().getOwnerDocument();
WSSecHeader secHeader = new WSSecHeader();
secHeader.insertSecurityHeader(doc);
builder.build(doc, secHeader);
} catch (Exception e) {
LOGGER.error("Unable to handle SOAP message", e);
return false;
}
}
return true;
}
...
}
我用XMLUtils.PrettyDocumentToString(doc)
检查了doc对象,看到它看起来像是由soupUI发送的XML - 所有身份验证信息(登录,密码,现时和创建时间)都已到位, mustUnderstand Security
标签的属性为真。
然后我遇到了错误:
javax.xml.ws.soap.SOAPFaultException:MustUnderstand标题:{{http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-wssecurity-secext-1.0.xsd}安全性未被理解
我找到了从Security
标记中删除mustUnderstand属性的建议,但它没有帮助。你有什么想法吗?
P.S。
Web服务端点位于 HTTPS 。
WSDL的政策部分:
<wsp:Policy wsu:Id="BasicHttpBinding_RelateService_policy">
<wsp:ExactlyOne>
<wsp:All>
<sp:TransportBinding>
<wsp:Policy>
<sp:TransportToken>
<wsp:Policy>
<sp:HttpsToken RequireClientCertificate="false"/>
</wsp:Policy>
</sp:TransportToken>
<sp:AlgorithmSuite>
<wsp:Policy>
<sp:Basic256/>
</wsp:Policy>
</sp:AlgorithmSuite>
<sp:Layout>
<wsp:Policy>
<sp:Lax/>
</wsp:Policy>
</sp:Layout>
<sp:IncludeTimestamp/>
</wsp:Policy>
</sp:TransportBinding>
<sp:SignedSupportingTokens>
<wsp:Policy>
<sp:UsernameToken
sp:IncludeToken="http://schemas.xmlsoap.org/ws/2005/07/securitypolicy/IncludeToken/AlwaysToRecipient">
<wsp:Policy>
<sp:WssUsernameToken10/>
</wsp:Policy>
</sp:UsernameToken>
</wsp:Policy>
</sp:SignedSupportingTokens>
<sp:Wss10>
<wsp:Policy/>
</sp:Wss10>
</wsp:All>
</wsp:ExactlyOne>
</wsp:Policy>
soapUI请求:
<soapenv:Envelope xmlns:ns="http://api.example.com/RelateService/1.0"
xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/">
<soapenv:Header>
<wsse:Security soapenv:mustUnderstand="1"
xmlns:wsse="http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-wssecurity-secext-1.0.xsd">
<wsse:UsernameToken wsu:Id="UsernameToken-37"
xmlns:wsu="http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-wssecurity-utility-1.0.xsd">
<wsse:Username>username</wsse:Username>
<wsse:Password
Type="http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-username-token-profile-1.0#PasswordText">
password
</wsse:Password>
<wsse:Nonce
EncodingType="http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-soap-message-security-1.0#Base64Binary">
li/0YK2wxrmrHL7Cg+etdQ==
</wsse:Nonce>
<wsu:Created>2012-02-21T08:59:10.262Z</wsu:Created>
</wsse:UsernameToken>
</wsse:Security>
</soapenv:Header>
<soapenv:Body>
<ns:RetrieveCustomerByEmail>
<ns:email>xxx@example.com</ns:email>
<ns:firstName/>
<ns:lastName/>
</ns:RetrieveCustomerByEmail>
</soapenv:Body>
</soapenv:Envelope>
我的要求:
<?xml version="1.0" encoding="UTF-8"?>
<S:Envelope xmlns:S="http://schemas.xmlsoap.org/soap/envelope/">
<S:Header>
<wsse:Security xmlns:wsse="http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-wssecurity-secext-1.0.xsd"
xmlns:wsu="http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-wssecurity-utility-1.0.xsd"
S:mustUnderstand="1">
<wsse:UsernameToken wsu:Id="UsernameToken-1">
<wsse:Username>username</wsse:Username>
<wsse:Password
Type="http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-username-token-profile-1.0#PasswordText">
password
</wsse:Password>
<wsse:Nonce
EncodingType="http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-soap-message-security-1.0#Base64Binary">
+jeleKO9zr0/wLjAIYcmSg==
</wsse:Nonce>
<wsu:Created>2012-02-21T09:42:03.760Z</wsu:Created>
</wsse:UsernameToken>
</wsse:Security>
</S:Header>
<S:Body>
<ns5:RetrieveCustomerByEmail xmlns="http://schemas.microsoft.com/2003/10/Serialization/Arrays"
xmlns:ns2="http://schemas.datacontract.org/2004/07/XXX.Service"
xmlns:ns3="http://schemas.datacontract.org/2004/07/XXX.Service.Relate.Contract"
xmlns:ns4="http://schemas.datacontract.org/2004/07/XXX.Service.Dto"
xmlns:ns5="http://api.example.com/RelateService/1.0"
xmlns:ns6="http://schemas.microsoft.com/2003/10/Serialization/">
<ns5:email>xxx@example.com</ns5:email>
<ns5:firstName/>
<ns5:lastName/>
</ns5:RetrieveCustomerByEmail>
</S:Body>
</S:Envelope>
答案 0 :(得分:16)
当服务无法处理标头时,您可能会收到此错误。该服务需要使用可解析标头的getHeaders()实现SOAPHandler。 对于上述故障,正确的实现如下
@Override
public Set<QName> getHeaders() {
QName securityHeader = new QName("http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-wssecurity-secext-1.0.xsd",
"Security");
HashSet<QName> headers = new HashSet<QName>();
headers.add(securityHeader);
return headers;
}
当服务实际上不安全但客户端正在尝试使用安全配置(可能使用XWSS安全配置)时,也可以获取此信息 为此,只需从浏览器中检查已发布的wsdl,并确保它包含预期的安全策略(将?wsdl附加到其端点URL)
答案 1 :(得分:8)
我找到了解决方案。需要以下依赖项:
<dependency>
<groupId>org.apache.cxf</groupId>
<artifactId>cxf-rt-frontend-jaxws</artifactId>
<version>2.2.3</version>
</dependency>
<dependency>
<groupId>org.apache.cxf</groupId>
<artifactId>cxf-rt-transports-http</artifactId>
<version>2.2.3</version>
</dependency>
关于这个主题的好文章和cxf的一些陷阱:http://www.logicsector.com/java/how-to-create-a-wsdl-first-soap-client-in-java-with-cxf-and-maven/
答案 2 :(得分:1)
这对我有用。基本上,它是@Joseph Rajeev Motha所宣告的想法的应用(尽管我在其他地方找到了,这里:https://dwuysan.wordpress.com/2012/04/02/jax-ws-wsimport-and-the-error-mustunderstand-headers-not-understood/#comment-215),但是他的答案没有提供样板,没有它,答案是非常神秘的。>
请注意,此顺序适用于独立案例(您自己发布Endpoint
的情况)。
创建一个SOAPHandler
来“理解”标题:
public class WSSESecurityUnderstandPretender implements SOAPHandler<SOAPMessageContext> {
@Override
public Set<QName> getHeaders() {
final QName securityHeader = new QName(
"http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-wssecurity-secext-1.0.xsd",
"Security",
"wsse");
final Set<QName> headers = new HashSet<>();
headers.add(securityHeader);
// notify the runtime that this is handled
return headers;
}
@Override
public boolean handleMessage(SOAPMessageContext context) {
// we must return true, or else the runtime will return
// wrong wrapper element name (like makeTransfer instead of
// makeTransferResponse)
return true;
}
@Override
public boolean handleFault(SOAPMessageContext context) {
// we must return true, or else the runtime will return
// wrong wrapper element name (like makeTransfer instead of
// makeTransferResponse)
return true;
}
@Override
public void close(MessageContext context) {
}
}
创建一个handler-chain.xml
文件并将其放在类路径中:
<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<javaee:handler-chains
xmlns:javaee="http://java.sun.com/xml/ns/javaee"
xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<javaee:handler-chain>
<javaee:handler>
<javaee:handler-class>com.mypackage.WSSESecurityUnderstandPretender</javaee:handler-class>
</javaee:handler>
</javaee:handler-chain>
</javaee:handler-chains>
通过对处理程序链文件的引用来注释实现类(用@WebService
注释的类)
@HandlerChain(file = "handler-chain.xml")
发布端点:
Endpoint endpoint = Endpoint.publish(url, impl);
handleMessage()
和handleFault()
必须返回true
。否则,您将得到诸如“意外的包装元素”之类的奇怪错误,因为将使用不同的包装元素名称。
答案 3 :(得分:-2)
如果您在使用Java 11的项目中遇到此问题,请尝试使用Apache CXF 3.3.x版本。
来自Apache CXF FAQ的以下答案:
CXF可以与JDK / Java 9+(10,11)一起运行吗?
是。 CXF将在下一个3.3.x版本中支持Java 9-11。