我正在使用SOAPUI工具访问部署在Weblogic 10.3.2中的JAX-WS Web服务
请求:
<soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" xmlns:ws="http://ws.pc3.polk.com/">
<soapenv:Header>
<wsse:Security soapenv:mustUnderstand="1" xmlns:wsse="http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-wssecurity-secext-1.0.xsd">
<wsu:Timestamp wsu:Id="Timestamp-1" xmlns:wsu="http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-wssecurity-utility-1.0.xsd">
<wsu:Created>2010-12-03T21:10:43Z</wsu:Created>
<wsu:Expires>2010-12-03T21:44:03Z</wsu:Expires>
</wsu:Timestamp>
<wsu:Timestamp wsu:Id="Timestamp-60" xmlns:wsu="http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-wssecurity-utility-1.0.xsd">
<wsu:Created>2010-12-03T20:10:39Z</wsu:Created>
<wsu:Expires>2010-12-03T20:43:59Z</wsu:Expires>
</wsu:Timestamp>
<wsse:UsernameToken wsu:Id="UsernameToken-59" xmlns:wsu="http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-wssecurity-utility-1.0.xsd">
<wsse:Username>rwerqre</wsse:Username>
<wsse:Password Type="http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-username-token-profile-1.0#PasswordText">ewrqwrwerqer</wsse:Password>
<wsse:Nonce EncodingType="http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-soap-message-security-1.0#Base64Binary">Nmw0ksmiOX+hkiSoWb2Rjg==</wsse:Nonce>
<wsu:Created>2010-12-03T20:10:39.649Z</wsu:Created>
</wsse:UsernameToken>
</wsse:Security>
</soapenv:Header>
<soapenv:Body>
<ws:getMetadata/>
</soapenv:Body>
</soapenv:Envelope>
响应:
<S:Envelope xmlns:S="http://schemas.xmlsoap.org/soap/envelope/">
<S:Body>
<SOAP-ENV:Fault xmlns:SOAP-ENV="http://schemas.xmlsoap.org/soap/envelope/">
<faultcode>SOAP-ENV:MustUnderstand</faultcode>
<faultstring>MustUnderstand headers:[{http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-wssecurity-secext-1.0.xsd}Security] are not understood</faultstring>
</SOAP-ENV:Fault>
</S:Body>
</S:Envelope>
答案 0 :(得分:9)
您可以为{http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-wssecurity-secext-1.0.xsd}Security
配置一个虚拟SOAPHandler,将此标题标记为“已理解”。
或者您可以更改SOAP请求(在调用者端)以在安全标头中设置mustUnderstand="0"
。
带有mustUnderstand="0"
的示例安全性SOAP标头:
<S:Header xmlns:S="http://schemas.xmlsoap.org/soap/envelope/">
<wsse:Security S:mustUnderstand="0" xmlns:wsse="http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-wssecurity-secext-1.0.xsd">
<wsse:UsernameToken>
<wsse:Username>USERNAME</wsse:Username>
<wsse:Password wsse:Type="http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-username-token-profile-1.0#PasswordText">PASSWORD</wsse:Password>
</wsse:UsernameToken>
</wsse:Security>
</S:Header>
答案 1 :(得分:7)
经过大量研究,本文解决了这个问题。
答案 2 :(得分:2)
根据WS安全规范: 在解密加密的报头块之后,处理器必须根据SOAP处理指南处理解密的报头块。如果充分处理标头块所需的任何内容保持加密状态,或者解密的SOAP标头未被理解,并且解密的标头块上的S12:mustUnderstand或S11:mustUnderstand属性的值为true,则接收方必须引发故障。请注意,为了在这种情况下遵守SOAP处理规则,处理器必须回滚处理安全头的任何持久效果,例如存储接收到的令牌。 所以请检查CallbackHandlers的配置。
答案 3 :(得分:2)
问题在于处理程序。您需要在处理程序实现中添加以下内容
public Set<QName> getHeaders() {
final QName securityHeader = new QName(
"http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-wssecurity-secext-1.0.xsd",
"Security",
"wsse");
final HashSet headers = new HashSet();
headers.add(securityHeader);
return headers;
}
答案 4 :(得分:-1)
在SOAP UI Navigator中,
右键单击您的项目 - >显示项目视图 - &gt; WS-Security配置 - &gt;传出WS-Security配置 取消选中必须明白,然后发送请求。