Question

iv在C＃中使用此算法来获取给定的字符串，删除任何空格，然后返回结果。是的，有一百万种方法可以做到这一点但我想让我自己的算法独立于标准类库。而且，我知道有一百万种方法可以用不同的方式来表达类似的算法，但是，请在这里请光临。

如果给定字符串中的第一个字符不是空格，则算法可以正常工作。但是如果第一个字符有空格，则返回的字符串包含正确的字符数量，但字符是“空白”。至少在打印时到控制台。我一直盯着这段代码几个小时，尝试这个，尝试这个，但是，对于我的生活，我无法弄清楚导致问题的原因。我吓死了甚至发布这个，因为有人可能会想出一个让我看起来迟钝的简单修复然后iv每个人都有时间，但是，iv看着，看着，在这里，那里。我需要帮助！看看代码吧。

public static string RemoveSpaces(string arg)
    {
        char[] temp = arg.ToCharArray();
        int newLength = 0;

        //Calculate number of characters that arent spaces.
        for (int e = 0; e < temp.Length; e++)
        {
            if (temp[e] != ' ')//If not a space,
            {
                newLength++;//then increment number of characters.
            }
        }

        //Now use that number as size in new array
        char[] newString = new char[newLength];

        //Copy characters that arent spaces to the new char array.
        for (uint e = 0, e2 = 0; e < temp.Length; e++, e2++)
        {
            //NOTE: e2 (and e) is a uint because it can end up negative for a 
            //short period.
            if (temp[0] == ' ')//If the FIRST element is a space
            {
                e2--;//Then dont let e2 be "truely" incremented in next cycle.
                continue;
                //e (and e2) will now be incremented by the loop.
                //but since we just decremented e2 it will be 1 behind e.
                //So we wont be skipping an element in newString if
                //we arent going to copy anything to that element.
                //Same thing happens in the other if statement below.
                //(Where the copying really happens)
            }

            if (temp[e] != ' ')//If element e is NOT a space,
            {
                newString[e2] = temp[e];//then copy that element to newString.
            }
            else//If element e IS a space
            {
                e2--;//Then dont let e2 be truely incremented in next cycle.
                //Cycle is complete so no use for continue; here.
            }
        }

        return new string(newString);//Done!
    }

Answer 1

不要在每次迭代中递增e2，只在角色不是空格时递增它。

试试这个：

public static string RemoveSpaces(string arg)
{
    int newLength = 0;

    //Calculate number of characters that arent spaces.
    foreach (char ch in arg)
    {
        if (ch != ' ')//If not a space,
        {
            newLength++;//then increment number of characters.
        }
    }

    //Now use that number as size in new array
    char[] newString = new char[newLength];

    //Copy characters that arent spaces to the new char array.
    int pos = 0;
    foreach (char ch in arg)
    {
        if (ch != ' ')//If element e is NOT a space,
        {
            newString[pos++] = ch;//then copy that element to newString.
        }
    }

    return new string(newString);//Done!
}

Answer 2

只有在写字符时才会增加e2。

Answer 3

或者只是这样做：

static string RemoveSpaces(String s)
{
    StringBuilder sb = new StringBuilder();
    foreach (char c in s)
    {
        if (c != ' ')
        {
            sb.Append(c);
        }
    }
    return sb.ToString();
}

Answer 4

我知道你不需要内置算法，但str = str.Replace(" ", "");是最容易记住的“现实生活”。另外，我想提请你注意空格不仅仅是' '。这些是C＃中的所有空格：char [] spaces = { ' ', '\b', '\t', '\v', '\f', '\n', '\r' };（最后两个是换行符）。

Answer 5

你为什么不使用

MyString.Replace(" ", "");

??????

我该如何修复这个字符串操作算法？

5 个答案: