using namespace std;
//a class that will handle all the calculations requested by user
class MathOperations{
public:
void Message();
int setSum(int,int);
int setSuB(int,int);
int setMul(int,int);
float setDiv(float,float *);
int setSqrt(int);
};
//Implementation:
void MathOperations:: Message(){
cout<< " Welcome. This program simulates a calculator "<<endl;
}
// implementing the setters methods.
int MathOperations::setSum(int a, int b){
int total;
total = a + b;
return total;
}
int MathOperations:: setSuB(int a, int b){
int total;
total = a - b;
return total;
}
int MathOperations:: setMul(int a, int b){
int total;
total = a * b;
return total;
}
float MathOperations:: setDiv(float a, float *b){
float result;
if(b ==0){
cout << "Using the Default Value of 1 because you can't devide by 0"<<endl;
}
else
result = (a / *b);
return result;
}
int MathOperations::setSqrt(int Square){
int total;
total = sqrt(Square);
return total;
}
int main(int argc, const char * argv[])
{
//creating instances of class MathOperations
MathOperations add, sub, mul, div, sqrt;
///creating variable to hold user input
int fnum;
float snum;
char opt= '0';
//propt user for values
cout << " Enter a Number"<<endl;
cin >> fnum;
cout << " Enter a second number " <<endl;
cin >> snum;
float total = div.setDiv(fnum, &snum);
cout << total <<endl;
cout << " What would you like to do '+','-','*','/' ?"<<endl;
cin >> opt;
switch (opt) {
case '+' :
{
int total = add.setSum(fnum, snum);
cout << " The Total Sum of both numbers is " << total <<endl;
}
break;
case '-' :
{
int total = sub.setSuB(fnum, snum);
cout << " The Subtraction of both Numbers is " << total << endl;
}
break;
case '*' :
{
int total = mul.setMul(fnum, snum);
cout << " The Multiplication of both Numbers is " << total << endl;
}
break;
case '/' :
{
int total = div.setDiv(fnum, &snum);
cout << " The Division of both Numbers is " << total <<endl;
}
default:
cout << " Not a valid Option"<<endl;
}
}
该部门工作不正常。我在这做错了什么?我正在尝试用它内部的数学运算创建一个类。我是初学者,想在这里做一些练习。你能告诉我具体做错的事吗?
答案 0 :(得分:0)
函数div的第二个参数不应该是指针。至少我没有看到它成为指针的任何理由。
所以只需删除*和&amp;来自变量snum。
答案 1 :(得分:0)
你不是在setDiv函数中保护自己不被0除,因为你不是先将第二个浮点数比作0。您只是将其地址与NULL进行比较。
错误信息没有意义:程序没有以任何方式“使用1”。
如果指针恰好为NULL,则返回未初始化的值。
答案 2 :(得分:0)
如果您说您使用的是1而不是0,则永远不会将b的值更改为1.