Question

我想用subprocess.Popen()运行一个进程，并通过python shell与它进行通信，就像subprocess.Popen通常的行为一样。除此之外，我想讨论将STDIN和STDOUT记录到日志文件中。

我该怎么做？

Answer 1

假设话语性意味着漫游和漫游意味着所有人都在同一个文件中，那么下面的代码片段就是你所要求的。

通过歧视来源和互动来讨论日志记录

覆盖类似问题here

的沟通方法

import subprocess

def logcommunicate(self, s):
    self.logfilehandle.write("Input "+s)
    std = self.oldcommunicate(s)

    self.logfilehandle.write("Output "+std[0])
    return std

subprocess.Popen.oldcommunicate = subprocess.Popen.communicate
subprocess.Popen.communicate = logcommunicate
logfh = open("/tmp/communicate.log", "a")

proc = subprocess.Popen(['cat'], stdin=subprocess.PIPE, stdout=subprocess.PIPE)
proc.logfilehandle = logfh

result = proc.communicate("hello there\n")
print result

以歧视来源进行讨论记录

首先使用StringIO而不是文件，然后继承StringIO以覆盖其打开的write方法，以附加时间戳和源。然后编写一个自定义比较函数，根据时间戳和源，首先是时间戳，然后是源输入然后输出

进行排序

 with open("file.log","wb") as in logfile:
 out = MyOutPutStringIO.StringIO() 
 in = MyInputStringIO.StringIO()
 subprocess.Popen(cmd, shell=True, universal_newlines = True, stdin=in, stdout=out)

 #Then after you are done
 linestotal = []
 for line in in.readlines():
     linestotal.append(line)
 for line in out.readlines():
     linestotal.append(line)

 linestotal.sort(customsortbasedontimestampandinput)

 for line in linestotal.readlines():
    logwrite.write(line)

讨论日志记录

 with open("file.log","wb") as in logfile:
 subprocess.Popen(cmd, shell=True, universal_newlines = True, stdin=logfile, stdout=logfile)

相反的情况如下所示

草书记录

 with open("stdout.txt","wb") as out:
 with open("stderr.txt","wb") as err:
 with open("stdin.txt","wb") as in:
 subprocess.Popen(cmd, shell=True, universal_newlines = True, stdin=in,stdout=out,stderr=err)

记录过程'STDIN和STDOUT

1 个答案: