获得一个月的第一个或最后一个星期五

时间:2009-05-29 03:20:38

标签: php datetime

我正在尝试编写像这样的日历函数

function get_date($month, $year, $week, $day, $direction)
{
    ....
}

$week是一个整数(1,2,3 ......),$ day是一天(太阳,周一,......)或数字,以较容易的为准。方向有点混乱,因为它做了不同的计算。

举个例子,让我们来电话

get_date(5, 2009, 1, 'Sun', 'forward');

它使用默认值,并获得5月的第一个星期日,即2009-05-03。如果我们打电话

get_date(5, 2009, 2, 'Sun', 'backward');

,它返回五月的第二个星期日,即2009-05-24。

12 个答案:

答案 0 :(得分:22)

与语言无关的版本:

要获得该月的第一天,请从该月的第一天开始:yyyy-mm-01。使用任何可用的函数来给出与星期几相对应的数字。从你想要的那天减去那个数字;例如,如果该月的第一天是星期三(2)并且您正在寻找星期五(4),则从4减去2,留下2.如果答案是否定的,则添加7.最后将其添加到第一天这个月;就我而言,第一个星期五将是第三个。

要获得本月的最后一个星期五,请找到下个月的第一个星期五,并减去7天。

答案 1 :(得分:12)

也许它可以更快... ... 这对代码来说非常有趣。

请注意,$direction为1表示正向,-1表示向后以缓解情况:) 此外,$day以星期一的值1开头,星期日的7结束。

function get_date($month, $year, $week, $day, $direction) {
  if($direction > 0)
    $startday = 1;
  else
    $startday = date('t', mktime(0, 0, 0, $month, 1, $year));

  $start = mktime(0, 0, 0, $month, $startday, $year);
  $weekday = date('N', $start);

  if($direction * $day >= $direction * $weekday)
    $offset = -$direction * 7;
  else
    $offset = 0;

  $offset += $direction * ($week * 7) + ($day - $weekday);
  return mktime(0, 0, 0, $month, $startday + $offset, $year);
}

我用几个例子对它进行了测试,似乎总是有效,但请务必仔细检查一下;)

答案 2 :(得分:8)

strtotime()可以帮到你。例如

<?php
$tsFirst = strtotime('2009-04-00 next friday');
$tsLast = strtotime('2009-05-01 last friday');
echo date(DATE_RFC850, $tsFirst), " | ", date(DATE_RFC850, $tsLast);
打印
Friday, 03-Apr-09 00:00:00 CEST | Friday, 24-Apr-09 00:00:00 CEST

答案 3 :(得分:8)

PHP的内置时间函数使这很简单。

http://php.net/manual/en/function.strtotime.php

// Get first Friday of next month.
$timestamp = strtotime('first fri of next month');

// Get second to last Friday of the current month.
$timestamp = strtotime('last fri of this month -7 days');

// Format a timestamp as a human-meaningful string.
$formattedDate = date('F j, Y', strtotime('first wed of last month'));

请注意,我们总是希望确保我们已经定义了与strtotime一起使用的正确时区,以便PHP了解在何处计算相对于机器认为的时区的时间戳。

date_default_timezone_set('America/New_York');
$formattedDate = date('F j, Y', strtotime('first wed of last month +1 week'));

答案 4 :(得分:6)

无需计算或循环 - 使用strtotime()非常容易:

查找特定月份的特定日期的第N次或最后一次出现:

/////////////////////////////////////////////////////////////////
// Quick Code
/////////////////////////////////////////////////////////////////

// Convenience mapping.
$Names = array( 0=>"Sun", 1=>"Mon", 2=>"Tue", 3=>"Wed", 4=>"Thu", 5=>"Fri", 6=>"Sat" );

// Specify what we want
// In this example, the Second Monday of Next March
$tsInMonth = strtotime('March');
$Day = 1;
$Ord = 2;

// The actual calculations
$ThisMonthTS = strtotime( date("Y-m-01", $tsInMonth ) );
$NextMonthTS = strtotime( date("Y-m-01", strtotime("next month", $tsInMonth) ) );
$DateOfInterest = (-1 == $Ord) 
    ? strtotime( "last ".$Names[$Day], $NextMonthTS ) 
    : strtotime( $Names[$Day]." + ".($Ord-1)." weeks", $ThisMonthTS ); 


/////////////////////////////////////////////////////////////////
// Explanation
/////////////////////////////////////////////////////////////////

// Specify the month of which we are interested.
// You can use any timestamp inside that month, I'm using strtotime for convenience.
$tsInMonth = strtotime('March');

// The day of interest, ie: Friday.  
// It can be 0=Sunday through 6=Saturday (Like 'w' from date()).
$Day = 5;

// The occurrence of this day in which we are interested.  
// It can be 1, 2, 3, 4 for the first, second, third, and fourth occurrence of the day in question in the month in question.
// You can also use -1 to fine the LAST occurrence.  That will return the fifth occurrence if there is one, else the 4th.
$Ord = 3;

////////////////////////////////////////////////////////////////
// We now have all the specific values we need.
// The example values above specify the 3rd friday of next march
////////////////////////////////////////////////////////////////

// We need the day name that corresponds with our day number to pass to strtotime().
// This isn't really necessary = we could just specify the string in the first place, but for date calcs, you are more likely to have the day number than the string itself, so this is convenient.
$Names = array( 0=>"Sun", 1=>"Mon", 2=>"Tue", 3=>"Wed", 4=>"Thu", 5=>"Fri", 6=>"Sat" );

// Calculate the timestamp at midnight of the first of the month in question.
// Remember $tsInMonth is any date in that month.
$ThisMonthTS = strtotime( date("Y-m-01", $tsInMonth ) );

// Calculate the timestamp at midnight of the first of the FOLLOWING month.
// This will be used if we specify -1 for last occurrence.
$NextMonthTS = strtotime( date("Y-m-01", strtotime("next month", $tsInMonth) ) );

// Now we just format the values a bit and pass them to strtotime().
// To find the 1,2,3,4th occurrence, we work from the first of the month forward.
// For the last (-1) occurence,work we work back from the first occurrence of the following month.
$DateOfInterest = (-1 == $Ord) ?
    strtotime( "last ".$Names[$Day], $NextMonthTS ) : // The last occurrence of the day in this month.  Calculated as "last dayname" from the first of next month, which will be the last one in this month. 
    strtotime( $Names[$Day]." + ".($Ord-1)." weeks", $ThisMonthTS ); // From the first of this month, move to "next dayname" which will be the first occurrence, and then move ahead a week for as many additional occurrences as you need.

答案 5 :(得分:4)

echo date('Y-m-d',strtotime('last friday'));

答案 6 :(得分:2)

您可以使用mktime检索当月第一天的unix时间戳:

$firstOfMonth = mktime(0, 0, 0, $month, 1, $year);

当您拥有某个月第一天的日期时,可以使用date轻松检索该日期的工作日:

$weekday = date("N", $firstOfMonth);

从那里开始,只需要前进即可获得你所追求的日期。

答案 7 :(得分:1)

function get_date($month, $year, $week, $day) {
    # $month, $year: current month to search in
    # $week: 0=1st, 1=2nd, 2=3rd, 3=4th, -1=last
    # $day:  0=mon, 1=tue, ..., 6=sun

    $startday=1; $delta=0;
    if ($week < 0) {
        $startday = date('t', mktime(0, 0, 0, $month, 1, $year)); # 28..31
        $delta=1;
    }
    $start  = mktime(0, 0, 0, $month, $startday, $year);
    $dstart = date('w', $start)-1; # last of the month falls on 0=mon,6=sun
    $offset=$day-$dstart; if ($offset<$delta){$offset+=7;}
    $newday=$startday+$offset+($week*7);
    return mktime(0, 0, 0, $month, $newday, $year);
}

这对我有用,并且基于与语言无关的版本:-) 只是太糟糕了,我需要做三角形的事情(如果这个月的最后一天是想要的工作日,我们不需要减去7)

答案 8 :(得分:0)

了解当月的第一天和最后一天是什么(即2009年5月1日是星期五,2009年5月31日是星期天)我相信大多数PHP函数都使用星期一= 0,星期日= 6,因此星期五= 4,所以你知道星期日(6) - 星期五(4)= 2,然后31-2 = 29,这意味着本月的最后一个星期五是29日。对于第一个星期五,如果数字是负数,则加7,如果数字为0,则月份从星期五开始。

答案 9 :(得分:0)

使用DateTime类可以非常优雅地完成同样的工作。

$time_zone = new DateTimeZone('Europe/Ljubljana');

$first_friday_of_this_month = new DateTime('first Friday of this month', $time_zone);
$last_friday_of_this_month = new DateTime('last Friday of this month', $time_zone);

echo $first_friday_of_this_month->format('Y-m-d');  # 2015-11-06
echo $last_friday_of_this_month->format('Y-m-d');  # 2015-11-27

答案 10 :(得分:0)

这似乎每次都很完美;它需要提供任何日期并返回该月的最后一个星期五的日期,即使是在该月的5个星期五。

function get_last_friday_of_month($inDate) {
    $inDate = date('Y-m-24', strtotime($inDate));
    $last_friday = date('Y-m-d',strtotime($inDate.' next friday'));
    $next_friday = date('Y-m-d',strtotime($inDate.' next friday'));

    if(date('m', strtotime($last_friday)) === date('m', strtotime($next_friday))){
        $last_friday = $next_friday;
    }else{
        //
    }
    return $last_friday;
}

答案 11 :(得分:0)

以下是最快的解决方案,您可以在所有条件下使用。如果你稍微调整一下,你也可以得到一整天的数组。

function findDate($date, $week, $weekday){
    # $date is the date we are using to get the month and year which should be a datetime object
    # $week can be: 0 for first, 1 for second, 2 for third, 3 for fourth and -1 for last
    # $weekday can be: 1 for Monday, 2 for Tuesday, 3 for Wednesday, 4 for Thursday, 5 for Friday, 6 for Saturday and 7 for Sunday 

    $start = clone $date;
    $finish = clone $date;

    $start->modify('first day of this month');
    $finish->modify('last day of this month');
    $finish->modify('+1 day');

    $interval = DateInterval::createFromDateString('1 day');
    $period = new DatePeriod($start, $interval, $finish);

    foreach($period AS $date){
        $result[$date->format('N')][] = $date;
    }

    if($week == -1)
        return end($result[$weekday]);
    else
        return $result[$weekday][$week];
}


$date = DateTime::createFromFormat('d/m/Y', '25/12/2016');

# find the third Wednesday in December 2016
$result = findDate($date, 2, 3); 
echo $result->format('d/m/Y');

我希望这会有所帮助。

如果您需要任何进一步的信息,请与我们联系。