Question

任何Python开发人员多年来一直在使用Python的Unicode问题。但现在我遇到的情况让我疯了，我自己无法解决这个问题。现在已经花了1天，包括recherches ..

我的设置是一个小的Django应用程序，它通过SOAP（使用Suds）连接到远程系统，提取一些数据并在Django的数据库中查找它：

from myapp.models import Customer
client = suds.client.Client(...)
customer = client.service.getCustomerByEmail('foo@bar.com')

type(customer.email): <class 'suds.sax.text.Text'>

customer_exists = Customer.objects.filter(email=customer.email)

现在客户的电子邮件地址有一个德语Umlautü，它让Django提出如下例外：

Traceback (most recent call last):
  File "run_anatomy_client.py", line 19, in <module>
    print client.main()
  File "/Users/user/Documents/workspace/Wawi/application/myapp/client.py", line 282, in main
    if not Customer.objects.filter(email=customer.email.encode('latin1')):
  File "/Users/user/Documents/workspace/Wawi/application/myapp/client.py", line 76, in sync_customer
    if not customer_exists:
  File "/Users/user/Documents/workspace/Wawi/pyenv/lib/python2.7/site-packages/django/db/models/query.py", line 113, in __nonzero__
    iter(self).next()
  File "/Users/user/Documents/workspace/Wawi/pyenv/lib/python2.7/site-packages/django/db/models/query.py", line 107, in _result_iter
    self._fill_cache()
  File "/Users/user/Documents/workspace/Wawi/pyenv/lib/python2.7/site-packages/django/db/models/query.py", line 772, in _fill_cache
    self._result_cache.append(self._iter.next())
  File "/Users/user/Documents/workspace/Wawi/pyenv/lib/python2.7/site-packages/django/db/models/query.py", line 273, in iterator
    for row in compiler.results_iter():
  File "/Users/user/Documents/workspace/Wawi/pyenv/lib/python2.7/site-packages/django/db/models/sql/compiler.py", line 680, in results_iter
    for rows in self.execute_sql(MULTI):
  File "/Users/user/Documents/workspace/Wawi/pyenv/lib/python2.7/site-packages/django/db/models/sql/compiler.py", line 735, in execute_sql
    cursor.execute(sql, params)
  File "/Users/user/Documents/workspace/Wawi/pyenv/lib/python2.7/site-packages/django/db/backends/util.py", line 43, in execute
    logger.debug('(%.3f) %s; args=%s' % (duration, sql, params),
UnicodeEncodeError: 'ascii' codec can't encode character u'\xfc' in position 28: ordinal not in range(128)

我已经玩过encode（），decode（），改变了源文件的编码以及数据库布局，目前看起来如下：

mysql> show variables like '%character%';
+--------------------------+-----------------------------------------+
| Variable_name            | Value                                   |
+--------------------------+-----------------------------------------+
| character_set_client     | latin1                                  |
| character_set_connection | latin1                                  |
| character_set_database   | utf8                                    |
| character_set_filesystem | binary                                  |
| character_set_results    | latin1                                  |
| character_set_server     | latin1                                  |
| character_set_system     | utf8                                    |
| character_sets_dir       | /opt/local/share/mysql5/mysql/charsets/ |
+--------------------------+-----------------------------------------+
8 rows in set (0.00 sec)

奇怪的是 - 如果我设置一个跟踪点并在Django shell中执行完全相同的行，那么在使用encode（）时它可以正常工作：

(Pdb) Customer.objects.filter(email=customer.email)
*** UnicodeEncodeError: 'ascii' codec can't encode character u'\xfc' in position 28:     ordinal not in range(128)
(Pdb) Customer.objects.filter(email=customer.email.encode('utf-8'))
[]

我会感激任何提示......

Answer 1

suds.sax.text.Text继承自unicode

class Text(unicode):
    """
    An XML text object used to represent text content.
    @ivar lang: The (optional) language flag.
    @type lang: bool
    @ivar escaped: The (optional) XML special character escaped flag.
    @type escaped: bool
    """

如果您想使用，可以编码为UTF-8。

email = customer.email.encode("utf-8")
customer_exists = Customer.objects.filter(email=email)

Answer 2

我花了2个多小时试图弄清楚发生了什么，以及为什么在将Suds数据结构中的值分配给对象的字段后，我无法保存Django对象。

正如@guillaumevincent所提到的，Suds Text类继承自unicode，并且实现不是100％正确，因此Django在尝试执行某些操作后失败，这将与基本unicode类型一起使用。

所以对于我会做的问题的例子

customer_exists = Customer.objects.filter(email=unicode(customer.email))

就我而言，我也是这样做的

django_obj.field_name = suds_obj.field_name

希望这可以节省一些时间：）

Django＆amp; Suds：使用QuerySet时的UnicodeEncodeError

2 个答案: