我有以下AR has_many,belongs_to relations:
联盟 - >会议 - >分部 - >队
我有一个如下所示的事件模型:
class Event < ActiveRecord::Base
belongs_to :league
belongs_to :home_team, :class_name => 'Team', :foreign_key => :home_team_id
belongs_to :away_team, :class_name => 'Team', :foreign_key => :away_team_id
validate :same_league
def same_league
return if home_team.blank? || away_team.blank?
errors.add :base, "teams must be in the same league" if home_team.league != away_team.league
end
end
还有一些工厂:
FactoryGirl.define do
factory :league do
name 'NFL'
end
end
Factory.define :conference do |f|
f.name 'NFC'
f.association :league
end
Factory.define :division do |f|
f.name 'North'
f.association :conference
end
Factory.define :team do |f|
f.name 'Packers'
f.locale 'Green Bay'
f.association :division
end
FactoryGirl.define do
factory :event do
association :league
association :home_team, :factory => :team
association :away_team, :factory => :team
end
end
所有这些,我将如何为same_league验证方法编写规范?
describe Event do
pending 'should not allow home_team and away_team to be from two different leagues'
end
我的问题是了解在不同联盟中创建两个团队并将其中一个与home_team相关联,另一个与事件模型中的away_team相关联的最简单方法。
答案 0 :(得分:3)
您可以存储使用工厂生成的实例,然后显式使用其ID来填充后续工厂的外键。
我在这里创建两个联赛,然后设置两个测试。其中一个赛事有两支球队在同一个联赛中,另一支球队有两支不同联赛的球队。这样我就可以测试事件对象是否正确验证:
describe Event do
before(:each) do
@first_league = Factory(:league)
@second_league = Factory(:league)
end
it "should allow the home_team and away_team to be from the same league" do
home_team = Factory(:team, :league_id => @first_league.id)
away_team = Factory(:team, :league_id => @first_league.id)
event = Factory(:event, :home_team_id => home_team.id, :away_team_id => away_team.id)
event.valid?.should == true
end
it "should not allow the home_team and away_team to be from two different leagues" do
home_team = Factory(:team, :league_id => @first_league.id)
away_team = Factory(:team, :league_id => @second_league.id)
event = Factory(:event, :home_team_id => home_team.id, :away_team_id => away_team.id)
event.valid?.should == false
end
end