Question

如何打印出json对象中的选定字段而不必为其创建类，此时它打印出整个json对象，但我只想打印出选定的字段，例如Console.WriteLine（ response.venues.name）;

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using Newtonsoft.Json;
using Newtonsoft.Json.Linq;

namespace FourSquareTest
{
class Program
{
    static void Main(string[] args)
    {
        using (var webClient = new System.Net.WebClient())
        {
            var json = webClient.DownloadString("https://api.foursquare.com/v2/venues/search?ll=40.7,-74&query=mcdonalds&client_id=XXXXXXX&client_secret=XXXXXXXX&v=20120101");
            // Now parse with JSON.Net

            JObject parsed = JObject.Parse(json);
            foreach (var pair in parsed)
            {
                Console.WriteLine("{0}: {1}", pair.Key, pair.Value);

            }

        }


    }
}
}

Answer 1

尝试

 JObject parsed = JObject.Parse(json);
 JToken response = parsed["response"];
 JArray venues = (JArray)response["venues"];
 JValue names = (JValue)venues[1]["name"];

但是我没有要测试的库，所以这只是基于文档。

从json对象中打印选择值

1 个答案: