Question

从webservice，我收到一个json对象。

来自json_decode的

var_dump（$ getUsercodes，true）给了我：

Array(549) {
["Jackson Kim"]=> array(2) { ["codeA"]=> string(1) "x" ["codeB"]=> string(1) "y" } 
["Richardson"]=> array(2) { ["codeA"]=> string(1) "x" ["codeB"]=> string(1) "y" } 
["Jenson Webb"]=> array(2) { ["codeA"]=> string(1) "x" ["codeB"]=> string(1) "y" } 
["Makai Pate"]=> array(2) { ["codeA"]=> string(1) "x" ["codeB"]=> string(1) "y" } ....

相同 - ＆gt;来自json_decode（$ getUsercodes，false）的var_dump给了我：

object(stdClass)#3 (549) {
["Jackson Kim"]=> object(stdClass)#2 (2) { ["codeA"]=> string(1) "x" ["codeB"]=> string(1) "y" } 
["Richardson"]=> object(stdClass)#4 (2) { ["codeA"]=> string(1) "x" ["codeB"]=> string(1) "y" } 
["Jenson Webb"]=> object(stdClass)#5 (2) { ["codeA"]=> string(1) "x" ["codeB"]=> string(1) "y" } 
["Makai Pate"]=> object(stdClass)#6 (2) { ["codeA"]=> string(1) "x" ["codeB"]=> string(1) "y" } 
....

如何只打印名字？ '杰克逊金'

我试过了：

$result = json_decode ($getUsercodes, true)

echo $result[0]

它给了我未定义的偏移量？

Answer 1

您可以使用：

$result = json_decode ($getUsercodes, true);
reset($array);  // This function reset array index to 1st member.
$first_key = key($array);  // This function returns first index of the array where the pointer is.
echo $first_key;  // So, this will print the first name

要获得更多密钥：请查看此示例。

$people = array("Peter", "Joe", "Glenn", "Cleveland");

echo current($people) . "<br>"; // Will print 'Peter'
echo next($people) . "<br>"; // Will print 'Joe'
echo next($people) . "<br>"; // Will print 'Glenn'
echo reset($people); // Will print 'Peter'

Answer 2

这是获取数组

的第一个键值的方法

$result = json_decode ($getUsercodes, true)   
$first_value = reset($result);

来自php webservice（json对象）的打印值

2 个答案: