读取开放简历的mms流

时间:2012-02-01 23:15:39

标签: c++ visual-studio opencv mms

有没有办法用open cv读取mms流进行直接分析?

我正在尝试用c ++做一个小项目。我不知道如何将mms插入opencv。

我觉得不需要在visual studio中添加一个库。

mms流上只有视频正在阅读:

mms://s3ewm.castup.net/991450009-52.wmv?ct=IL&rg=BZ&aid=145&tkn=20120201230602&ts=0&cu=FC1B06E9-7ABE-4B1C-9B2A-7A5C6019E99F

更新

我找到了这个链接:Microsoft msdn

1 个答案:

答案 0 :(得分:0)

here有人确实通过vlc包获得了mms。

struct ctx
{
   IplImage* image;
   HANDLE mutex;
   uchar*    pixels;
};

void *lock(void *data, void**p_pixels)
{
    struct ctx *ctx = (struct ctx*)data;
    WaitForSingleObject(ctx->mutex, INFINITE);
     *p_pixels = ctx->pixels;   
    return NULL;

}
void display(void *data, void *id){
   (void) data;
   assert(id == NULL);
}
void unlock(void *data, void *id, void *const *p_pixels){
   struct ctx *ctx = (struct ctx*)data;
   /* VLC just rendered the video, but we can also render stuff */
   uchar *pixels = (uchar*)*p_pixels;
   cvShowImage("image", ctx->image);
   ReleaseMutex(ctx->mutex);
   assert(id == NULL); /* picture identifier, not needed here */
}

int main()
{
   cvNamedWindow("image", CV_WINDOW_AUTOSIZE);
   libvlc_media_t* media = NULL;
   libvlc_media_player_t* mediaPlayer = NULL;
   char const* vlc_argv[] = {"--plugin-path", "C:\\Users\\Oscar\\Documents\\libvlc\\vlc-1.1.4"};
   libvlc_instance_t* instance = libvlc_new(2,vlc_argv);
   mediaPlayer = libvlc_media_player_new(instance);
   media = libvlc_media_new_path(instance, "mms://81.89.49.210/musicbox");

   struct ctx* context = ( struct ctx* )malloc( sizeof( *context ) );
   context->mutex = CreateMutex(NULL, FALSE,NULL);
   context->image = cvCreateImage(cvSize(VIDEO_WIDTH, VIDEO_HEIGHT), IPL_DEPTH_8U, 4);
        context->pixels = (unsigned char *)context->image->imageData;

   libvlc_media_player_set_media( mediaPlayer, media);
   libvlc_video_set_callbacks(mediaPlayer, lock, unlock, display, context);
        libvlc_video_set_format(mediaPlayer, "RV32", VIDEO_WIDTH, VIDEO_HEIGHT, VIDEO_WIDTH*4);
   libvlc_media_player_play(mediaPlayer);


   while(1)
   {
   }
   return 0;
}