我正在修改一个教程,我发现如何创建一个接受多个客户端的TCP聊天服务器。我最终也会创建一个客户端类,但到目前为止我正在用TELNET测试它。
我希望服务器不断检查输入,以便我可以使用关键字来预先形成服务器功能。所以用字符串“EXIT”来断开客户端和字符串“Name:”以打印“OK”。
这就是我的想法,但它不起作用:
public void run()
{
String line;
try
{
while(true)
{
if (input.readline("EXIT"))//Should close and remove client
{
clients.remove(this);
users.remove(name);
break;
}
if(input.readline("Name:"))//Should print OK with username
{
System.out.println("OK");
}
boradcast(name,line); // method of outer class - send messages to all
}// end of while
} // try
catch(Exception e)
{
System.out.println(e.getMessage());
}
} // end of run()
}
}
这是整个服务器类
// Chat Server runs at port no. 9020
import java.io.*;
import java.util.*;
import java.net.*;
import static java.lang.System.out;
public class TCPServer
{
Vector<String> users = new Vector<String>();
Vector<HandleClient> clients = new Vector<HandleClient>();
int PORT = 9020;
int NumClients = 10;
public void process() throws Exception
{
ServerSocket server = new ServerSocket(PORT,NumClients);
out.println("Server Connected...");
while( true)
{
Socket client = server.accept();
HandleClient c = new HandleClient(client);
clients.add(c);
} // end of while
}
public static void main(String ... args) throws Exception
{
new TCPServer().process();
} // end of main
public void boradcast(String user, String message)
{
// send message to all connected users
for (HandleClient c : clients)
if (!c.getUserName().equals(user))
{
c.sendMessage(user,message);
}
}
class HandleClient extends Thread
{
String name = "";
BufferedReader input;
PrintWriter output;
public HandleClient(Socket client) throws Exception
{
// get input and output streams
input = new BufferedReader(new InputStreamReader(client.getInputStream())) ;
output = new PrintWriter (client.getOutputStream(),true);
output.println("Welcome to Bob's Chat Server!\n");
// read name
output.println("Please Enter a User Name: ");
name = input.readLine();
users.add(name); // add to vector
output.println("Welcome "+name+" we hope you enjoy your chat today");
start();
}
public void sendMessage(String uname,String msg)
{
output.println( uname + ":" + msg);
}
public String getUserName()
{
return name;
}
public void run()
{
String line;
try
{
while(true)
{
if (input.readline("EXIT"))
{
clients.remove(this);
users.remove(name);
break;
}
if(input.readline(name))
{
System.out.println("OK");
}
boradcast(name,line); // method of outer class - send messages to all
}// end of while
} // try
catch(Exception e)
{
System.out.println(e.getMessage());
}
} // end of run()
} // end of inner class
} // end of Server
答案 0 :(得分:3)
当输入行等于当前用户名时,如果不确切知道你想要做什么,我认为这更像是你正在寻找的东西:
public void run(){
try{
while(true){
String line = input.readLine();
if("EXIT".equals(line)){
clients.remove(this);
users.remove(name);
break;
}else if(name.equals(line)){
System.out.println("OK");
}
boradcast(name, line); // method of outer class - send messages to all
}// end of while
} // try
catch(Exception e){
System.out.println(e.getMessage());
}
} // end of run()
这解决了一些问题:
input.readline
不是方法,但input.readLine
是 - 并且它不接受任何参数。 (这应该显示为编译错误。)line
字符串分配任何内容。name
进行比较 - 无论用户为上一行输入了什么内容。