我想使用以下代码删除列表中的重复项,但它不起作用。有人可以开导我吗?感谢。
public sealed class Pairing
{
public int Index { get; private set; }
public int Length { get; private set; }
public int Offset { get; private set; }
public Pairing(int index, int length, int offset)
{
Index = index;
Length = length;
Offset = offset;
}
}
class MyComparer : IEqualityComparer<Pairing>
{
public bool Equals(Pairing x, Pairing y)
{
return ((x.Index == y.Index) && (x.Length == y.Length) && (x.Offset == y.Offset));
}
public int GetHashCode(Pairing obj)
{
return obj.GetHashCode();
}
}
class Program
{
static void Main(string[] args)
{
List<Pairing> ps = new List<Pairing>();
ps.Add(new Pairing(2, 4, 14));
ps.Add(new Pairing(1, 2, 4));
ps.Add(new Pairing(2, 4, 14));
var unique = ps.Distinct(new MyComparer());
foreach (Pairing p in unique)
{
Console.WriteLine("{0}\t{1}\t{2}", p.Index, p.Length, p.Offset);
}
Console.ReadLine();
}
}
答案 0 :(得分:4)
根据IEnumerable.Distinct页面上的示例,您需要实现GetHashCode(),以便相等的对象返回相同的哈希码。如果您没有覆盖对象中的GetHashCode(),则为not guaranteed to return the same hashcode。
// If Equals() returns true for a pair of objects
// then GetHashCode() must return the same value for these objects.
public int GetHashCode(Product product)
{
//Check whether the object is null
if (Object.ReferenceEquals(product, null)) return 0;
//Get hash code for the Name field if it is not null.
int hashProductName = product.Name == null ? 0 : product.Name.GetHashCode();
//Get hash code for the Code field.
int hashProductCode = product.Code.GetHashCode();
//Calculate the hash code for the product.
return hashProductName ^ hashProductCode;
}
答案 1 :(得分:1)
定义GetHashCode以返回唯一答案会导致Distinct按预期工作;
public int GetHashCode(Pairing obj)
{
if (obj==null) return 0;
var hc1 = obj.Index.GetHashCode();
var hc2 = obj.Length.GetHashCode();
var hc3 = obj.Offset.GetHashCode();
return hc1 ^ hc2 ^ hc3;
}