Question

我有以下xml（我无法编辑）：

<?xml version="1.0" encoding="UTF-8"?>

<ns0:prices xmlns:ns0="http://schemas.some.com/sadas/Output">
  <pricepoint>
    <esid>
      ENG.GPL.DAY_AHEAD.PROMPT.PH.M
    </esid>
    <observationdate>20120123</observationdate>
    <observationtime>0000</observationtime>
    <price>22.1250</price>
    <quote>Q</quote>
  </pricepoint>
  <pricepoint>
    <esid>
      ENG.NBP.DAY_AHEAD.PROMPT.PH.M
    </esid>
    <observationdate>20120123</observationdate>
    <observationtime>0000</observationtime>
    <price>53.8500</price>
    <quote>Q</quote>
  </pricepoint>
  <pricepoint>
    <esid>
      ENG.NCG.DAY_AHEAD.PROMPT.PH.M
    </esid>
    <observationdate>20120123</observationdate>
    <observationtime>0000</observationtime>
    <price>22.0750</price>
    <quote>Q</quote>
  </pricepoint>
  <pricepoint>
    <esid>
      ENG.TTF.DAY_AHEAD.PROMPT.PH.M
    </esid>
    <observationdate>20120123</observationdate>
    <observationtime>0000</observationtime>
    <price>21.9500</price>
    <quote>Q</quote>
  </pricepoint>
  <pricepoint>
    <esid>
      ENG.ZEEBRUGGE.DAY_AHEAD.PROMPT.PH.M
    </esid>
    <observationdate>20120123</observationdate>
    <observationtime>0000</observationtime>
    <price>53.6500</price>
    <quote>Q</quote>
  </pricepoint>
</ns0:prices>

以及我希望将以下对象映射到：

[Serializable]
public class Prices 
{

    public List<Pricepoint> prices { get; set; }
}

[Serializable]
public class Pricepoint
{

    public string Esid { get; set; }

    public DateTime Observationdate { get; set; }

    public int Observationtime { get; set; }

    public double Price { get; set; }

    public string Quote { get; set; }

}

使用以下方法：

    public static object Deserialize(Type typeToDeserialize,byte[] bytes)
    {
        var mem = new MemoryStream(bytes);
        var ser = new XmlSerializer(typeToDeserialize);
        return ser.Deserialize(mem);
    }

由Deserialize(typeof(Prices), byteArrayofXMLfile);

发出

但是我确实收到了关于xml的命名空间行的错误：

There is an error in XML document (3, 2)

我无法弄清楚我在这里做错了什么？

Answer 1

修改：只是重新阅读，看到你问的是命名空间。使用Namespace的{{1}}属性，如下所示。

您需要告诉XmlSerializer哪些标签通过属性映射到哪些属性：

XmlRootAttribute

Answer 2

这样的东西？

XmlRootAttribute r = new XmlRootAttribute("prices");
r.Namespace = "http://schemas.some.com/sadas/Output";

var ser = new XmlSerializer(typeof(Prices),r);
return ser.Deserialize(mem);

PS：您还应该考虑标记名称的大小写

Answer 3

通过让visual studio为我生成类来解决问题：

C:\>xsd latest.xml
Microsoft (R) Xml Schemas/DataTypes support utility
[Microsoft (R) .NET Framework, Version 4.0.30319.1]
Copyright (C) Microsoft Corporation. All rights reserved.
Writing file 'C:\latest.xsd'.

C:\>xsd latest.xsd /classes
Microsoft (R) Xml Schemas/DataTypes support utility
[Microsoft (R) .NET Framework, Version 4.0.30319.1]
Copyright (C) Microsoft Corporation. All rights reserved.
Writing file 'C:\latest.cs'.

将xml反序列化为c＃对象

3 个答案: