Question

我正在尝试将xml序列化为对象，但在序列化后，我的传输协议列表为空。我很确定这很容易，但我找不到我的错误。

我有以下xml

<transport-agreements type="array">
   <transport-agreement>
     <id type="integer">1047</id>
     <description>Standard</description>
     <products type="array">
       <product>not important</product>
     </products>
   </transport-agreement>
   <transport-agreement>
     <id type="integer">1048</id>
     <description>Standard</description>
     <products type="array">
       <product>not important</product>
    </products>
   </transport-agreement>
</transport-agreements>

我有以下代码：

var resultContent = await response.Content.ReadAsStreamAsync();
var serializer = new XmlSerializer(typeof(TransportAgreementRoot));
var transportAgreements = (TransportAgreementRoot)serializer.Deserialize(resultContent);

我的班级：

[Serializable, XmlRoot("transport-agreements")]

    public class TransportAgreementRoot
    {
        [XmlArrayItem("transport-agreement")]
        TransportAgreement[] TransportAgreements { get; set; }         
     }

    public class TransportAgreement
    {
        [XmlElement("description")]
        public string Description { get; set; }
        [XmlElement("id")]
        public int Id { get; set; }
        [XmlElement("number")]
        public string Number { get; set; }
        [XmlElement("carrier")]
        public Carrier Carrier { get; set; }
        [XmlArray("products")]
        [XmlArrayItem("product")]
        public Product[] Products { get; set; }

    }

Answer 1

您可以使用一些在线转换器，它们将为您提供完整的类图表。我最喜欢的是：this one

Answer 2

[XmlRoot("transport-agreements")]
public class TransportAgreementRoot
{
    [XmlElement("transport-agreement")]
    public TransportAgreement[] TransportAgreements { get; set; }
}

[XmlRoot("transport-agreement")]
public class TransportAgreement
{
    [XmlElement("description")]
    public string Description { get; set; }
    [XmlElement("id")]
    public int Id { get; set; }
    // other properties
}

Answer 3

我将XmlArray更改为XmlElement。数组会添加一个额外的标签，你在xml文件中没有。

   [Serializable, XmlRoot("transport-agreements")]

    public class TransportAgreementRoot
    {
        [XmlElement("transport-agreement")]
        TransportAgreement[] TransportAgreements { get; set; }
    }

将XML反序列化为对象C＃

3 个答案: