Question

我正在尝试使用HTTP POST在大学登录页面上提交用户信息。为此，我运行下面的postData（）方法。代码发布凭据并读取响应。在代码下方，我已经显示了响应状态行和响应实体显示的内容。（我编辑了安全性的用户名和密码;））。

它似乎是执行的，因为我收到了网站的回复，但我不知道如何解释它的说法或我需要做什么才能成功登录。有问题的网站有一个用户名字段（id = user），密码字段（id = pass）和登录按钮（id = submit）。它是一个安全的网站（https），但是现在我没有进行SSL连接，因为我只是想让这段代码正常工作。

我遇到的直接问题是：我是否可能需要SSL连接才能使其正常工作，并且Java是响应中提到的问题？

更多背景......这是在服务中完成的，这是唯一的任务。如果Java是问题，如何在没有webview的情况下启用它？

public void postData() {
    // Create a new HttpClient and Post Header
    HttpParams params = new BasicHttpParams();
    params.setParameter(CoreProtocolPNames.PROTOCOL_VERSION, HttpVersion.HTTP_1_1);
    HttpClient httpclient = new DefaultHttpClient(params);
    HttpPost httppost = new HttpPost("https://wiscmail.wisc.edu/login/");
    TextView info = (TextView) findViewById(R.id.info);
    EditText user = (EditText) findViewById(R.id.user);
    EditText pass = (EditText) findViewById(R.id.pass);

    try {
        // Add your data
        List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);
        nameValuePairs.add(new BasicNameValuePair("user", user.getText().toString()));
        nameValuePairs.add(new BasicNameValuePair("pass", pass.getText().toString()));
        httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));

        // Execute HTTP Post Request
        HttpResponse response = httpclient.execute(httppost);
        Log.v(TAG, response.getStatusLine().toString());
        info.setText(response.getStatusLine().toString());

        HttpEntity responseEntity = response.getEntity();
        Log.v(TAG, responseEntity.toString());

        String response_string = inputStreamToString(response.getEntity().getContent()).toString();
        Log.v(TAG, response_string);

    } catch (ClientProtocolException e) {
        Log.v(TAG, "client protocol exception");
        info.setText("client protocol exception");
    } catch (IOException e) {
        Log.v(TAG, "IO exception");
        info.setText("IO exception");
    }
}

private StringBuilder inputStreamToString(InputStream is) {
    String line = "";
    StringBuilder total = new StringBuilder();

    // Wrap a BufferedReader around the InputStream
    BufferedReader rd = new BufferedReader(new InputStreamReader(is));

    // Read response until the end
    try {
        while ((line = rd.readLine()) != null) { 
            total.append(line); 
        }
    } catch (IOException e) {
        e.printStackTrace();
    }

    // Return full string
    return total;
}

response.getStatusLine

HTTP/1.1 200 OK

response.getEntity（）。的getContent（）

<html><head></head><body onLoad="document.relay.submit()">
<form method=post action="https://login.wisc.edu/?appurl=wiscmail.wisc.edu/login"
name=relay><input type=hidden name=pubcookie_g_req 
value="b25lPXdpc2NtYWlsLndpc2MuZWR1JnR3bz1XaXNjTWFpbCtMb2dpbiZ0aHJlZT0xJmZvdXI9YTUmZml2ZT1QT1NUJnNpeD13aXNjbWFpbC53aXNjLmVkdSZzZXZlbj1MMnh2WjJsdUx3PT0mZWlnaHQ9Jmhvc3RuYW1lPXdpc2NtYWlsLndpc2MuZWR1Jm5pbmU9MSZmaWxlPSZyZWZlcmVyPShudWxsKSZzZXNzX3JlPTAmcHJlX3Nlc3NfdG9rPTM5NjgzODc5MSZmbGFnPTA=">
<input type=hidden name=post_stuff value="user=username&pass=password">
<input type=hidden name=relay_url value="https://wiscmail.wisc.edu/PubCookie.reply">
<noscript><p align=center>You do not have Javascript turned on,   please click the
button to continue.<p align=center><input type=submit name=go value=Continue>
</noscript></form></html>

编辑：根据建议我尝试将一个setHeader添加到http客户端，但我从网站获得了相同的响应。

httppost.setHeader("Content-type", "application/x-www-form-urlencoded");
httppost.setHeader("Accept", "application/x-www-form-urlencoded");

解释HTTP POST响应

0 个答案: