Question

我无法说明为什么我的代码没有得到对帖子请求的回复。这是服务器的文档：

EMT-REST （JSON）访问的Web服务所有服务请求都被称为POST，因此所有参数都应添加到正文请求中响应是JSON格式的文本
所有方法请求都需要 idClient 和 passKey ，这些值由EMT根据请求提供。

网址为https://openbus.emtmadrid.es:9443/emt-proxy-server/last/

GetArriveStop POST

$ {SERVERURL} /geo/GetArriveStop.php

获取巴士到达信息到目标站点

请求

idClient API客户端标识符字符串

passKey API客户端密码字符串

idStop停止id字符串统计私人使用（不设置）字符串

cultureInfo EN | ES响应字符串的语言

响应

到达抵达名单

最后，这是我执行它的Android代码：

import java.io.InputStream;

import org.apache.http.HttpResponse;
import org.apache.http.client.HttpClient;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.entity.StringEntity;
import org.apache.http.impl.client.DefaultHttpClient;
import org.apache.http.util.EntityUtils;
import org.json.JSONObject;

import com.hmkcode.android.R;

import android.app.Activity;
import android.os.AsyncTask;
import android.os.Bundle;
import android.util.Log;
import android.view.View.OnClickListener;
import android.widget.EditText;
import android.widget.Toast;


public class MainActivity extends Activity{
    EditText etName;
protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        etName = (EditText) findViewById(R.id.etName);
        new HttpAsyncTask().execute("https://openbus.emtmadrid.es:9443/emt-proxy-server/last/geo/GetArriveStop.php");
}


    private class HttpAsyncTask extends AsyncTask<String, Void, String> {
        @Override
        protected String doInBackground(String... urls) {


            return POST(urls[0]);
        }
        // onPostExecute displays the results of the AsyncTask.
        @Override
        protected void onPostExecute(String result) {
            Toast.makeText(getBaseContext(), "Data Sent and received!", Toast.LENGTH_LONG).show();
            etName.setText(result); //editText from layout
       }
    }


    public static String POST(String url){
        Log.i("METHOD POST INICIATED", "METHOD POST");
        InputStream inputStream = null;
        String result = "";
        try {

            // 1. create HttpClient
            HttpClient httpclient = new DefaultHttpClient();

            // 2. make POST request to the given URL
            HttpPost httpPost = new HttpPost(url);

            String json = "";

            // 3. build jsonObject
            JSONObject jsonObject = new JSONObject();
            jsonObject.accumulate("idClient","EMT.SERVICIOS.EMTJSONBETA");
            jsonObject.accumulate("passKey", "4F4EEB75-A822-41E3-817B-AB301D5DA321");
            jsonObject.accumulate("idStop", "488");
            jsonObject.accumulate("cultureInfo", "ES");


            // 4. convert JSONObject to JSON to String
            json = jsonObject.toString();
            // ** Alternatives way to convert Person object to JSON string usin Jackson Lib 

            // 5. set json to StringEntity
            StringEntity se = new StringEntity(json);

            // 6. set httpPost Entity
            httpPost.setEntity(se);

            // 7. Set some headers to inform server about the type of the content   
            httpPost.setHeader("Accept", "application/json");
            httpPost.setHeader("Content-type", "application/json");

            Log.i("HTTP EXECUTION", "right before line httpclient.exeute");
            // 8. Execute POST request to the given URL
            HttpResponse httpResponse = httpclient.execute(httpPost);
            Log.i("AFTER HTTP EXECUTION", "right before line hhtpclient.exeute");
            // 9. receive response as inputStream
            //inputStream = httpResponse.getEntity().getContent();
            result = EntityUtils.toString(httpResponse.getEntity());

            // 10. convert inputstream to string
            //if(inputStream != null){
                Log.i("CONVERT INPUT", "convertInputStreamToString");
                //result = convertInputStreamToString(inputStream);
            //}else{
                Log.i("NO INPUT", "result = did not work!");
                //result = "Did not work!";
            //}

        } catch (Exception e) {
            Log.d("InputStream", e.getLocalizedMessage());
        }

        // 11. return result
        return result;
    }
}

在这行代码之后它不再继续了 // 8.对给定的URL执行POST请求 HttpResponse httpResponse = httpclient.execute（httpPost）;

我不知道为什么。

我已经尝试过以另一台服务器为例，它工作正常，也许我在标题中遗漏了一些东西。服务器的完整文档：http://blog.emtmadrid.es/wp-content/uploads/2014/05/API-REST-JSON-v-1.1.rar

Android HTTP POST响应没有响应

0 个答案: