到目前为止,我有以下内容,但是如果没有一堆凌乱的if语句,就无法找到一个整齐的方法来获取方向字母。有任何想法吗?理想情况下,我想用一个类别扩展CLLocation类来执行此操作。
-(NSString *)nicePosition{
double latitude = [self.latitude doubleValue];
double longitude = [self.longitude doubleValue];
int latSeconds = (int)round(latitude * 3600);
int latDegrees = latSeconds / 3600;
latSeconds = abs(latSeconds % 3600);
int latMinutes = latSeconds / 60;
latSeconds %= 60;
int longSeconds = (int)round(longitude * 3600);
int longDegrees = longSeconds / 3600;
longSeconds = abs(longSeconds % 3600);
int longMinutes = longSeconds / 60;
longSeconds %= 60;
//TODO: Use N,E,S,W notation in lat/long
return [NSString stringWithFormat:@"%i° %i' %i\", %i° %i' %i\"", latDegrees, latMinutes, latSeconds, longDegrees, longMinutes, longSeconds];
}
为了记录,我做了以下事情。
-(NSString *)nicePosition{
double latitude = [self.latitude doubleValue];
double longitude = [self.longitude doubleValue];
int latSeconds = (int)round(abs(latitude * 3600));
int latDegrees = latSeconds / 3600;
latSeconds = latSeconds % 3600;
int latMinutes = latSeconds / 60;
latSeconds %= 60;
int longSeconds = (int)round(abs(longitude * 3600));
int longDegrees = longSeconds / 3600;
longSeconds = longSeconds % 3600;
int longMinutes = longSeconds / 60;
longSeconds %= 60;
char latDirection = (latitude >= 0) ? 'N' : 'S';
char longDirection = (longitude >= 0) ? 'E' : 'W';
return [NSString stringWithFormat:@"%i° %i' %i\" %c, %i° %i' %i\" %c", latDegrees, latMinutes, latSeconds, latDirection, longDegrees, longMinutes, longSeconds, longDirection];
}
答案 0 :(得分:13)
标准方式:
char lonLetter = (lon > 0) ? 'E' : 'W';
char latLetter = (lat > 0) ? 'N' : 'S';
答案 1 :(得分:9)
以下是基于Daniel解决方案的一些Objective-C:
- (NSString*)coordinateString {
int latSeconds = (int)(self.latitude * 3600);
int latDegrees = latSeconds / 3600;
latSeconds = ABS(latSeconds % 3600);
int latMinutes = latSeconds / 60;
latSeconds %= 60;
int longSeconds = (int)(self.longitude * 3600);
int longDegrees = longSeconds / 3600;
longSeconds = ABS(longSeconds % 3600);
int longMinutes = longSeconds / 60;
longSeconds %= 60;
NSString* result = [NSString stringWithFormat:@"%d°%d'%d\"%@ %d°%d'%d\"%@",
ABS(latDegrees),
latMinutes,
latSeconds,
latDegrees >= 0 ? @"N" : @"S",
ABS(longDegrees),
longMinutes,
longSeconds,
longDegrees >= 0 ? @"E" : @"W"];
return result;
}
答案 2 :(得分:3)
这是C#中的解决方案:
void Run(double latitude, double longitude)
{
int latSeconds = (int)Math.Round(latitude * 3600);
int latDegrees = latSeconds / 3600;
latSeconds = Math.Abs(latSeconds % 3600);
int latMinutes = latSeconds / 60;
latSeconds %= 60;
int longSeconds = (int)Math.Round(longitude * 3600);
int longDegrees = longSeconds / 3600;
longSeconds = Math.Abs(longSeconds % 3600);
int longMinutes = longSeconds / 60;
longSeconds %= 60;
Console.WriteLine("{0}° {1}' {2}\" {3}, {4}° {5}' {6}\" {7}",
Math.Abs(latDegrees),
latMinutes,
latSeconds,
latDegrees >= 0 ? "N" : "S",
Math.Abs(longDegrees),
longMinutes,
longSeconds,
latDegrees >= 0 ? "E" : "W");
}
这是一个示例运行:
new Program().Run(-15.14131211, 56.345678);
new Program().Run(15.14131211, -56.345678);
new Program().Run(15.14131211, 56.345678);
打印哪些:
15° 8' 29" S, 56° 20' 44" W
15° 8' 29" N, 56° 20' 44" E
15° 8' 29" N, 56° 20' 44" E
希望这会有所帮助,并且它做对了。祝你好运!
答案 3 :(得分:3)
如果你想在swift中做到这一点,你可以做出类似的事情:
import MapKit
extension CLLocationCoordinate2D {
var latitudeDegreeDescription: String {
return fromDecToDeg(self.latitude) + " \(self.latitude >= 0 ? "N" : "S")"
}
var longitudeDegreeDescription: String {
return fromDecToDeg(self.longitude) + " \(self.longitude >= 0 ? "E" : "W")"
}
private func fromDecToDeg(input: Double) -> String {
var inputSeconds = Int(input * 3600)
let inputDegrees = inputSeconds / 3600
inputSeconds = abs(inputSeconds % 3600)
let inputMinutes = inputSeconds / 60
inputSeconds %= 60
return "\(abs(inputDegrees))°\(inputMinutes)'\(inputSeconds)''"
}
}
答案 4 :(得分:1)
关于Alex的答案,这里是Swift 3中带有输出元组的解决方案。它返回元组中的坐标。
此外,它确实扩展了CLLocationDegrees类,并且不需要额外的参数。
import MapKit
extension CLLocationDegrees {
func degreeRepresentation() -> (northOrEast: Bool, degrees: Int, minutes: Int, seconds: Int) {
var inputSeconds = Int(self * 3600)
let inputDegrees = inputSeconds / 3600
inputSeconds = abs(inputSeconds % 3600)
let inputMinutes = inputSeconds / 60
inputSeconds %= 60
return (inputDegrees > 0, abs(inputDegrees), inputMinutes, inputSeconds)
}
}
答案 5 :(得分:0)
int latSeconds = (int)round(abs(latitude * 3600));
这是错误的!适当的是
int latSeconds = abs(round(latitude * 3600));